Question

The length of segment EF is 12 cm.

Answer 1

Answer:

EF is the longest side of △DEF,

DF = 6 cm and

DE = 6 StartRoot 3 EndRoot cm.

Step-by-step explanation:

The angle ∠ EDF = 90° of the right triangle Δ DEF and ∠ DEF = 30° and ∠ EFD = 60°.

The hypotenuse EF is 12 cm.

Now, Sin ∠ EFD = DE/EF

⇒ $\sin 60^{\circ} = \frac{DE}{12}$

⇒ DE = 6√3 cm.

Again, Cos ∠EFD = DF/EF

⇒ $\cos 60^{\circ} = \frac{DF}{12}$

⇒ DF = 6 cm.

Therefore, EF is the longest side of △DEF, DF = 6 cm and DE = 6 StartRoot 3 EndRoot cm. (Answer)

Answer 2

Answer:

ABC

Step-by-step explanation: