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lianna [129]
2 years ago
10

you want to make a rectangular dog pen using 20 yards od fencing. The side lengths must be in whole yards. create as many differ

ent rectangular pens as you can
Mathematics
1 answer:
Marina CMI [18]2 years ago
8 0
Rectangular with whole numbers
perimiter=legnth+legnth+width+width=2l+2w
therefor
p=2l+2w=2(l+w)
p/2=l+w

perimiter=20
20=2l+2w
divide by 2 to make simpler
10=l+w
find all combos
l>w so
l=9 and w=1
l=8 and w=2
l=7 and w=3
l=6 and w=4

combos
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2 years ago
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1/5, 2/3, 5/8 from least to greatest on a number line
Svetllana [295]

1/5, then 5/8, then 2/3

8 0
3 years ago
Which represents the inverse of the function f(x) = 4x?
nekit [7.7K]

Answer:

\displaystyle h(x) = \frac{1}{4}x

Step-by-step explanation:

Sinse in this case you are dealing with direct variation, all you are doing is taking the <em>multiplicative</em><em> </em><em>inverse</em><em> </em>of 4, which is ¼:

\displaystyle f(x) = 4x \rightarrow f^{-1}(x) = \frac{1}{4}x

This option is not an answer choise. Perhaps there was a typographical errour.

I am joyous to assist you at any time.

5 0
2 years ago
Help I just don’t know what I’m supposed to do?
Sidana [21]
Multiple each number I think
4 0
3 years ago
you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
1 year ago
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