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LUCKY_DIMON [66]
2 years ago
12

Sam is planning to start a pool cleaning business from his home. He has decided on a radius of 30 miles from his

Mathematics
2 answers:
My name is Ann [436]2 years ago
7 0

Answer:

The answer is D

Step-by-step explanation:

GOT IT right ED 2021

Olin [163]2 years ago
3 0

Answer:

D. Since pools are not often removed from a property, 43% of homes with a pool means a strong potential customer base now, with the existing home owners, and later, with new home owners.

Step-by-step explanation:

did on edge 2021

You might be interested in
HELP PLEASE!
algol13

Step-by-step explanation:

5×4=20. 20×9=180

+

9×4=36. 36/9=4

180+4=184

answer=184

when a number is next to a letter it mean to multiply

and / means to divide

3 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
2 years ago
...I don’t understand umm can anyone help me smh-
Anna007 [38]
Answer:

{Rounded to the nearest Hundredths place}

1) Mercury= 170.55
2) Venus= 277.86
3) Earth= 389.62
4) Mars= 401.29

Explanation:

Mercury: 3.3022 x 10^19= 170.549894825 which rounds to 170.55

Earth: 5.9722 x 10^24= 389.618945662 which rounds to 389.62

Venus: 4.8675 x 10^21= 277.855972801 which rounds to 277.86

Mars: 6.4185 x 10^23= 401.287714067 which rounds to 401.29

•So smallest to largest would be• 170.55, 277.86, 389.62, and 401.29

[I hope this helps][Sorry if it doesn’t make sense]

3 0
3 years ago
Find the angle of RMQ.
faust18 [17]

Answer:

22

Step-by-step explanation:

since there is a bisector that makes the two angles equal. you first need to find x then with x you can add the angles to get the biggest angle witch is RMQ

2x+1 = 4x-9

1=2x-9

10=2x

5=x

x=5

RMQ=2x+1+4x-9

RMQ=2(5)+1+4(5)-9

RMQ=10+1+20-9

RMQ=11+11

RMQ=22

RMQ=16

8 0
3 years ago
5)
Natalija [7]

Answer:

i think the 2nd one

Step-by-step explanation:

7 0
2 years ago
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