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alexira [117]
3 years ago
10

The axis of symmetry for the graph of the function is f(x)=1/4x2+bc+10 is x=6. What is the value of b?

Mathematics
1 answer:
earnstyle [38]3 years ago
6 0

for f(x)=ax^2+bx+c, the axis of symmetry is x=\frac{-b}{2a}


given that axis of symmetry is x=6, \frac{-b}{2a}=6

we know that a=1/4 from the problem, so

6=\frac{-b}{2(\frac{1}{4})}

6=\frac{-b}{\frac{1}{2}}

6=-2b

divide by -2 both sides

-3=b

the value of b is -3

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