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cestrela7 [59]
3 years ago
13

Which of the following shows a loss of $900? A. +$900 B. $900 C. -$900 D. -$9.00

Mathematics
2 answers:
Dafna11 [192]3 years ago
8 0
Well if you had 900 and shows loss it would be c
Makovka662 [10]3 years ago
3 0
The answer is C, -$900.
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I need help with 2 and 5 and I need you to right down how you did it plz and thank you
anastassius [24]
Number 5 is 22 and 35
For example: 7+1=8, 8+2 =10, 10+3=13, 13+4=17, 17+5=22, 22+6=28, 28+7=35
5 0
2 years ago
The width of a rectangle is 3 cm less than the length.The area of the rectangle is 10cm^2. Write an equation that models the sit
ludmilkaskok [199]

Answer:

width is 2 and length is 5

Step-by-step explanation:

7 0
3 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Use the distributive property to simplify the expression 5 ( − 1 x − 6 + 6 y )
expeople1 [14]

Answer:

the answer should be -5x - 30 + 30 y

3 0
2 years ago
Read 2 more answers
In ΔKLM, the measure of ∠M=90°, the measure of ∠L=18°, and KL = 8.3 feet. Find the length of MK to the nearest tenth of a foot.
const2013 [10]

Answer:

2.6 ft

Step-by-step explanation:

8.3/sin 90 = MK/sin 18

MK = 8.3 sin 18 / sin 90

MK = 2.6 ft

7 0
3 years ago
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