Answer:
x = 2 , y = 11
Step-by-step explanation:
the diagonals of a parallelogram bisect each other , then
PT = TR , that is
y = 5x + 1 → (1)
QT = TS , that is
2y = 6x + 10 → (2)
substitute y = 5x + 1 into (2)
2(5x + 1) = 6x + 10
10x + 2 = 6x + 10 ( subtract 6x from both sides )
4x + 2 = 10 ( subtract 2 from both sides )
4x = 8 ( divide both sides by 4 )
x = 2
substitute x = 2 into either of the 2 equations for corresponding value of y
substituting into (1)
y = 5(2) + 1 = 10 + 1 = 11
Answer:
i think [after solving] that it is option B and C
Step-by-step explanation:
This is similar to the other question you posted. Follow the same steps as before.
First find g(41).
g(41) = sqrt{x - 5}
g(41) = sqrt{41 - 5}
g(41) = sqrt{36}
g(41) = 6
We now find f(6).
f(6) = -7(6) + 1
f(6) = -42 + 1
f(6) = -41
Answer:
(fºg)(41) = -41
Did you follow?