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hichkok12 [17]
3 years ago
13

How many Solutions are there for -6(3x+2)=2x-5-20x-7

Mathematics
1 answer:
jeka57 [31]3 years ago
5 0

First of all, expand the left hand side:

-18x-12 = 2x-5-20x-7

Sum like terms on the right hand side:

-18x-12 = -18x-12

As you can see, the equation turned to be an identity: it doesn't matter which value for x you are choosing: you're evaluating the same expression in both sides, so they will always be the same.

In other words, you're asking: which value for x should I choose so that -18x-12 and -18x-12 evaluate to the same number? Well, obvisouly any value for x will do.

So, there are infinitely many solutions to this equation, namely ever real number is a solution of this equation.

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Bob discovers a box with 30 identical, used, rechargeable batteries in his attic. Suppose each of them is equally likely have so
lukranit [14]

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

Bob discovers a box with 30 identical, used, rechargeable batteries in his attic.

Suppose each of them is equally likely have some charge in it, or to have run out of charge. What is the probability that:

a) All of them are out of charge?

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Answer:

Part A) P = 9.31x10⁻¹⁰

Part B) P = 5.529x10⁻⁴

Step-by-step explanation:

It is given that probability of success or failure is 50%

Let

failure = battery is out of charge

success = battery is not out of charge

Psuccess = p = 0.50

Pfailure = q = 1 - Psuccess = 0.50

Part A) All of them are out of charge?

The probability can be found by using binomial distribution formula

P = nCr (p^r) (q^n-r)

where r is the number of success

n = 30, r = 30 and n - r = 30 - 30 = 0

P = ₃₀C₃₀(0.50)³⁰(0.50)⁰

P = 9.31x10⁻¹⁰

Part B) 20% of them are out of charge?

Out of charge batteries = 0.20*30 = 6

n = 30, r = 24 and n - r = 30 - 24 = 6

P =₃₀C₆(0.50)²⁴(0.50)⁶

P = 5.529x10⁻⁴

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