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hichkok12 [17]
3 years ago
13

How many Solutions are there for -6(3x+2)=2x-5-20x-7

Mathematics
1 answer:
jeka57 [31]3 years ago
5 0

First of all, expand the left hand side:

-18x-12 = 2x-5-20x-7

Sum like terms on the right hand side:

-18x-12 = -18x-12

As you can see, the equation turned to be an identity: it doesn't matter which value for x you are choosing: you're evaluating the same expression in both sides, so they will always be the same.

In other words, you're asking: which value for x should I choose so that -18x-12 and -18x-12 evaluate to the same number? Well, obvisouly any value for x will do.

So, there are infinitely many solutions to this equation, namely ever real number is a solution of this equation.

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4.9t^2-2.78t-1.15=0 what is the value of T
zzz [600]

Answer:

t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

Step-by-step explanation:

Solve for t:

4.9 t^2 - 2.78 t - 1.15 = 0

4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:

(49 t^2)/10 - (139 t)/50 - 23/20 = 0

Multiply both sides by 10/49:

t^2 - (139 t)/245 - 23/98 = 0

Add 23/98 to both sides:

t^2 - (139 t)/245 = 23/98

Add 19321/240100 to both sides:

t^2 - (139 t)/245 + 19321/240100 = 75671/240100

Write the left hand side as a square:

(t - 139/490)^2 = 75671/240100

Take the square root of both sides:

t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

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greater than (>)

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x=9 and y=81

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