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Savatey [412]
4 years ago
5

Jack wants to bike from his house to Jill's house, which is located three blocks east and two blocks north of Jack's house. Afte

r biking each block, Jack can continue either east or north, but he needs to avoid a dangerous intersection one block east and one block north of his house. In how many ways can he reach Jill's house by biking a total of five blocks?
Mathematics
1 answer:
bija089 [108]4 years ago
7 0
Your answer would be 4.

\frac{2}{1} x \frac{3}{2}  = 6 choices and a total of  \frac{5}{10}=10 total
So then 10-6=4
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A rectangular sheet of paper 88cm×21cm is rolled along its length and cylinder is formed . find the total surface area of thecyl
vagabundo [1.1K]

length =88cm

breadth=21cm

when it is rolled it becomes cylinder

having circumference 88cm

2πr=88cm

r=88×7/44

r=14

h=21

total surface area of the cylinder =2πr(r+h).

=2×22/7×14(14+21)

=3080cm²

8 0
3 years ago
Read 2 more answers
40% remaining 8 minutes left how long with the entire download take 48 minutes 32 minutes 20 minutes or 8 minutes
RSB [31]

Answer:

20 minutes

Step-by-step explanation:

8÷.40=20

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5 0
3 years ago
mr. martin’s math test, which is worth 100 points, has 29 problems. each problem is worth either 5 points or 2 points. let x be
wariber [46]
Let x and y be the numbers of questions worth 5 and 2, respectively. There are a total of 29 questions which means that x + y should be 29. The equations that best describe the conditions are,
                                      x + y = 29
                                     5x + 2y = 100
Solving for x and y gives x = 14 and y = 15. Thus, there are 14 and 15 questions worth 5 and  2, respectively.
4 0
3 years ago
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See attached photo for solution

4 0
4 years ago
Solve this equation log3X + log3(x-6) = log3 7
ExtremeBDS [4]

Hello!

log₃(x) + log₃(x - 6) = log₃(7) <=>

<=> log₃(x * (x - 6)) = log₃(7) <=>

<=> log₃(x² - 6x) = log₃(7) <=>

<=> x² - 6x = 7 <=>

<=> x² - 6x - 7 = 0 <=>

<=> x² + x - 7x - 7 = 0 <=>

<=> x * (x + 1) - 7 * (x + 1) = 0 <=>

<=> (x + 1) * (x - 7) = 0 <=>

<=> x + 1 = 0 and x - 7 = 0 <=>

<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>

<=> x = 7

Good luck! :)

3 0
3 years ago
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