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Ber [7]
3 years ago
14

Which team has the best winning percentage?

Mathematics
1 answer:
Sonja [21]3 years ago
4 0
10 wins/ 6 losses= 1.667

13 wins/ 7 losses= 1.857..

32 wins/ 18 losses= 1.77..

6 wins/ 3 losses= 2

The last team has the highest win to loss ratio, and therefore has the highest winning percentage.

Final answer: Last team, 6 wins and 3 losses
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1)
almond37 [142]

Radio Barn : 200 + .15 x  x = the weekly sales

Woofer: 300 + .10x

set them equal to find when they are them same

200 + .15x = 300 + .10x

subtract .10x from both sides

200 +.15x -.10x = 300 + .10x-.10x

200 +.05x = 300

subtract 200 from each side

200+.05x -200 = 300-200

.05x = 100

divide each side by .05

.05x/.05 = 100/.05

x =2000

The 2 jobs pay the same when the weekly sales are 2000 dollars


2.  {x - 5 = -y}

{2y - 10 = -2x}

x-5 = -y

add 5 to each side

x = -y+5

multiply each side by -2

-2x = 2y -10

the 2 equations are the same, it has an infinite number of solutions

The system is dependent  since the 2 equations are the same line


3.  {2x = y - 7}

{4x - 2y - 14 = 0}

2x = y-7

subtract y-7 from each side

2x - (y-7) = 0

2x -y+7 =0

multiply by 2

4x -2y +14 =0

subtract the two equations

4x -2y +14 =0

4x - 2y - 14 = 0

---------------------------

               28 = 0

since this cannot happen   the lines will never cross ( parallel lines)

the system is inconsistent

5 0
3 years ago
A linear equation has more than one intercept. what can you conclude about the graph of the equation?
DanielleElmas [232]
A linear equation of the form :

y = mx+b

can have at the most ONE x-intercept and at the most ONE y-intercept

I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis

5 0
3 years ago
If the sum of a number and six is doubled, the result is eight less than the number
LekaFEV [45]
(x+6)2 = x - 8
give me one moment
8 0
3 years ago
√₂
snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

brainly.com/question/28350785

5 0
1 year ago
PLZ HELP ASAP Geometry help: 2x^2 + 2y^2 - 8x +10y +2=0
Alexxx [7]
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's


2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside

2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25

that is a circle center (2,-2.5) with radius √9.25

6 0
3 years ago
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