Find the slope of the line passing through the points (-3,1) and (-8,5)

To make concrete, the ratio of cement to sand is 1 : 3. If cement and sand are sold in bags of equal mass, how many bags of ceme

kotykmax [81]

Answer:

5 bags of cement are required.

Step-by-step explanation:

Since to make concrete, the ratio of cement to sand is 1: 3, if cement and sand are sold in bags of equal mass, to determine how many bags of cement are required to make concrete using 15 bags of sand the following calculation must be done:

Cement = 1

Sand = 3

3 = 15

1 = X

15/3 = X

5 = X

Therefore, 5 bags of cement are required.

3 0

3 years ago

Screenshot of the question

tamaranim1 [39]

9514 1404 393

Answer:

x = 1, x = 7

Step-by-step explanation:

You can see from the graph that the x-intercepts of f(x) are ...

0 = f(-3)

0 = f(3)

To find the corresponding values of x for f(x-4), we can solve ...

0 = f(x -4)

x -4 = -3 ⇒ x = 1

x -4 = 3 ⇒ x = 7

The x-intercepts of the function after translation 4 units right are ...

x = 1, x = 7

__

Your sketch will be the same curve moved 4 units to the right. (Add 4 to every x-value shown.)

3 0

3 years ago

The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.

malfutka [58]

The number of pencils sold on the first day is 5 pencils.

The number of notebooks sold on the first day is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day 35 notebooks.

Step-by-step explanation:

Given data,

The total number of notebooks in the store = 45 notebooks.
The total number of Pencils in the store = 15 pencils.
The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

In the first day :

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day = x

And, the number of notebooks sold on the first day = 2x (Twice as pencils).

In the second day :

The number of sale of notebooks and pencils are given by,

For every 7 notebooks sold, 2 pencils were sold.

The number of pencils sold on the second day = 2y

The number of notebooks sold on the second day = 7y

The equation is framed for number of notebooks sold on each day :

The number of notebooks sold ⇒ 2x + 7y = 45 -------(1)

The equation is framed for number of pencils sold on each day :

The number of pencils sold: x + 2y = 15 ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

2x + 7y = 45

- (2x + 4y) = 30

3y = 15

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day = x ⇒ 5 pencils

The number of notebooks sold on the first day = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day = 2y ⇒ 10 pencils

The number of notebooks sold on the second day = 7y ⇒ 35 notebooks.

8 0

3 years ago

How to find the discriminant of

Sonbull [250]

the discriminant b^2 - 4ac when the equation is in the form of ax^2 +bx+c=0

13x^2-16x = x^2 -x

we need to get in it the standard form

subtract x^2 from each side

12x^2 -16x = -x

add x to each side

12x^2 -15x = 0

12x^2 -15x -0 =0

a=12 b=-15 c=0

b^2 -4ac

the discriminant = b^2

b^2 = (-15)2 = 225

5 0

3 years ago

Where does the point (0, - 3) lie?

gregori [183]

An ordered pair is written like this, ( x, y ). In this case x = 0 and y = -3. On a graph the vertical line is the y-axis and the horizontal line is the x-axis. The origin is point ( 0, 0 ). To the left of the origin on the x-axis is the negative number line and to the right is the positive number line. On the y-axis, south of the origin is the negative number line and north is the positive number line. When you plot a point on a graph you do x first, so if x equals 1, you would move one right, -1, one left. IF y were to equal 2 then from the place where you are on the x-axis, 1, you would move two up, -2, two down. In this case x = 0 so you would stay at the origin, and y = -3 so you would move 3 down. So ( 0, -3 ) would lie negative y-axis. The answer is D.

3 0

3 years ago