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masha68 [24]
3 years ago
15

What are the names of the two angles? *

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

C or the 3rd one

Step-by-step explanation:

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Find the equation of the tangent line to the graph of f(a) = sec(a) at the point (0, 1).
Paladinen [302]
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0

y = mx + c
1 = 0(0) + c
c = 1

Therefore, required equation is
y = 1.
5 0
3 years ago
Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)
Amanda [17]

Answer:

f_x(x,y,z)=4\sin (y-z)

f_x(x,y,z)=4x\cos (y-z)

f_z(x,y,z)=-4x\cos (y-z)

Step-by-step explanation:

The given function is

f(x,y,z)=4x\sin (y-z)

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

f_x(x,y,z)=4(1)\sin (y-z)

f_x(x,y,z)=4\sin (y-z)

Differentiate partially w.r.t. y and x, z are constants.

f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)

f_y(x,y,z)=4x\cos (y-z)

Differentiate partially w.r.t. z and x, y are constants.

f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)

f_z(x,y,z)=4x\cos (y-z)(-1)

f_z(x,y,z)=-4x\cos (y-z)

Therefore, the first partial derivatives of the function are f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z).

4 0
3 years ago
Find the area of the shaded region. Round the the nearest tenth.
Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = \frac{\theta}{360^{\circ} }\pi r^2

Area of sector = \frac{123}{360} \times 3.14 \times (18.6)^2

Area of sector = 371.157 m^2

Area of triangle = \frac{1}{2} \times a \times b \times Sin x

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = \frac{1}{2} \times 18.6 \times 18.6 \times Sin 123

Area of triangle = 145.073 m^2

So, Area of shaded region = Area of sector - Area of triangle

                                            =371.157 m^2-145.073 m^2

                                            =226.084 m^2

Hence the area of the shaded region is 226.084 sq.m.

5 0
3 years ago
Which graph shows a function where f(2)=4?
White raven [17]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP<br><br><br> What is the equation of the line shown?
Ivenika [448]

So, let's start off with explaining what these different questions mean;

y = |x + c| Shifts the graph c units left.

y = |x - c| Shifts the graph c units right.

y = |x| + c Shifts the graph c units up.

y = |x| - c Shifts the graph c units down.

(0,0) Is the starting point on any graph like this. So, determine the answer by going through the list of answers.

I believe the answer is y = 2x.

I would like to know if I am wrong so contact me!!

8 0
3 years ago
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