Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:



Step-by-step explanation:
The given function is

We need to find first partial derivatives of the function.
Differentiate partially w.r.t. x and y, z are constants.


Differentiate partially w.r.t. y and x, z are constants.


Differentiate partially w.r.t. z and x, y are constants.



Therefore, the first partial derivatives of the function are
.
Answer:
226.084 sq.m.
Step-by-step explanation:
Radius of circle = 18.6 cm
Area of sector = 
Area of sector = 
Area of sector = 
Area of triangle = 
a = OA = radius = 18.6 cm
b = OB = radius = 18.6 cm
x =123 °
Substitute the values in the formula
Area of triangle = 
Area of triangle = 
So, Area of shaded region = Area of sector - Area of triangle
=
=
Hence the area of the shaded region is 226.084 sq.m.
Answer:
A
Step-by-step explanation:
So, let's start off with explaining what these different questions mean;
y = |x + c| Shifts the graph c units left.
y = |x - c| Shifts the graph c units right.
y = |x| + c Shifts the graph c units up.
y = |x| - c Shifts the graph c units down.
(0,0) Is the starting point on any graph like this. So, determine the answer by going through the list of answers.
I believe the answer is y = 2x.
I would like to know if I am wrong so contact me!!