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densk [106]
3 years ago
5

A line passes through the point(4,-1) and (2,3). What is the slope of the line

Mathematics
1 answer:
sasho [114]3 years ago
7 0
Slope is found using the equation (y2-y1)/(x2-x1)
So we can plug the numbers into the equation

(-1)-3/ 4-2
(-1)-3= -4
4-2=2 

The equation is now -4/2
-4/2= -2

So the slope of the line is -2

Which can also be written as y=-2x
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You roll fair6-sided die what is P(roll a 2)?
creativ13 [48]

Answer:

1/6

Step-by-step explanation:

It is a 6 sided die, so you have 6 possibilities, so that is going to be you denominator.

There is only one number 2 on the die, so you have 1 as your numerator.

5 0
3 years ago
Read 2 more answers
The annual interest rate of Mike's savings account is 4.8%, and simple interest is calculated monthly. What is the periodic inte
Reptile [31]

The correct option will be: d. 0.4%

For finding the periodic interest rate , we need to divide the annual interest rate by the number of times interest calculated in a year.

Here, the simple interest is calculated monthly, that means the number of times interest calculated in a year will be 12.

Annual interest rate is 4.8%

So, the periodic interest rate = \frac{4.8}{12}= 0.4%

5 0
3 years ago
Read 2 more answers
Bart uses 3/12 cup milk to make muffin. Write a fraction that is equivalent to 3/12
vichka [17]
Your fraction that is equal to 3/12 is 1/4
8 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
At the soup to nuts cafeteria, larry orders two pieces of toast and a bagel, which comes out to $\$1.30$. Curly orders a bagel a
kotegsom [21]

Let us take costs of a piece of toast = $t, , one bagel cost=$b and a muffin cost=$m.

Larry

Two pieces of toast and a bagel cost  = $1.30

2t+b=1.30   -------------equation(1)

Let us solve the equation(1) for t in terms of b, because we need to find one bagel cost.

Subtracting b from both sides we get

2t+b-b=1.30-b

2t= 1.30-b

Dividing by 2 on both sides.

2t/2= (1.30-b)/2

t= (1.30-b)/2

Curly

A bagel and a muffin cost = $2.50.

b + m = 2.50 -------------equation(2)

Solving equation for m in terms of b, we get

m= 2.50-b.

Moe

A piece of toast, two bagels, and three muffins cost = $6.95

t + 2b + 3m = 6.95    ......................equation(3).

Substituting t= (1.30-b)/2 and m= 2.50-b in equation (3)

(1.30-b)/2 + 2b + 3(2.50-b) = 6.95 .

Multiplying each term by 2 to get rid 2 from denominator of (1.30-b).

2*(1.30-b)/2 + 2*2b + 2*3(2.50-b) = 2*6.95

1.30-b + 4b + 6(2.50-b) = 13.90.

1.30 - b + 4b  +15 - 6b = 13.90

Combining like terms

-3b +16.30 = 13.90

Subtracting 16.30 from both sides.

-3b +16.30-16.30 = 13.90-16.30.

-3b= -2.4

Dividing both sides by -3.

-3b/-3 = -2.4/-3

b = 0.8

Therefore, cost of one bagel = $0.80.

7 0
3 years ago
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