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Crazy boy [7]
3 years ago
7

Write the answer in the form of fraction decimal and percentage

Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0
Seriously you beg for people to do your hw?
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What are the factors of 36
nasty-shy [4]
1,36. 2,18. 3,12. 4,9. 6,6. I thibk thats all
4 0
3 years ago
What is 6pi to the 6 power.
Tomtit [17]

Hey there!

6(3.14)^6

= 6(3.14^6)

= 6(3.14 * 3.14 * 3.14 * 3.14 * 3.14 * 3.14)

= 6(9.8596 * 9.8596 * 9.8596)

= 6(97.21171216 * 9.8596)

= 6(5,750.811583)

≈ 5750.81158328



Therefore, the answer should be:

5,750.81158328



Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

6 0
2 years ago
A person invests 3500 dollars in a bank. The bank pays 6.25% interest compounded annually. To the nearest tenth of a year, how l
olya-2409 [2.1K]
18.328 or 18.3 years
8 0
3 years ago
The measure of angle O is 7pi/6. The measure of its reference angle is.... ° and sin O is .....
scoray [572]
\frac{7 \pi }{6} is in the 3rd quadrant... (It is also 210 degrees)
To find the reference angle (which is the distance to the x-axis)
\frac{7 \pi }{6} - \pi = \frac{ \pi }{6}  (or 30 degrees)

sin \frac{ \pi }{6} = \frac{1}{2}
6 0
3 years ago
Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language. Describe the
taurus [48]

Answer:

The distribution of sample proportion Americans who can order a meal in a foreign language is,

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The sample size of Americans selected to disclose whether they can order a meal in a foreign language is, <em>n</em> = 200.

The sample selected is quite large.

The Central limit theorem can be applied to approximate the distribution of sample proportion.

The distribution of sample proportion is,

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})

3 0
3 years ago
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