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masya89 [10]
2 years ago
8

Winston-Salem is halfway between Boone and Raleigh. Burlington is halfway between Winston- Salem and Raleigh. If Boone is locate

d at the coordinates (-1,3) and Raleigh is at (-5, 9), what are the coordinates of Burlington?
Mathematics
1 answer:
loris [4]2 years ago
7 0

Answer:

The answer is (-4, 15/2)

Step-by-step explanation:

Let the Boone be x, Winston-Salem be y, Raleigh be z and Burlington be m.

We are given that Winston-Salem is halfway between Boone and Raleigh. Burlington is halfway between Winston- Salem and Raleigh.

If Boone is located at the coordinates (-1,3) and Raleigh is at (-5, 9).

We will use Midpoint Formula

( \frac{x _{1} + x _{2}}{2} , \frac{y _{1} + y _{2}}{2} ) \\

Where,

x₁ = (-1) and x₂ = (-5)

y₁ = 3 and y₂ = 9

Now, We will find Co-ordinates of y i.e., Winston-Salem.

So,

( \frac{( - 1) + ( - 5)}{2} , \frac{3 + 9}{2} ) \\

( \frac{( - 1 - 5)}{2} , \frac{12}{2} ) \\

( \frac{ - 6}{2} , \frac{12}{2} ) \\

( - 3,6)

Here, The coordinates of y i.e., Winston-Salem is (-3, 6).

Now, We will find Co-ordinates of m i.e., Burlington.

So,

Again, Using of Midpoint Formula;

Where,

x₁ = (-3) and x₂ = (-5)

y₁ = 6 and y₂ = 9

So,

( \frac{( - 3) + ( - 5)}{2} , \frac{6 + 9}{2} ) \\

( \frac{( - 3 - 5)}{2} , \frac{15}{2} ) \\

( \frac{( -8)}{2} , \frac{15}{2} ) \\

( - 4  , \frac{15}{2} ) \\

Thus, The coordinates of Burlington is (-4, 15/2).

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Question 1

probability between 2.8 and 3.3

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The probability of the value between z=-0.73 and z=0.49 is given by 
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A screenshot of z-table that allows reading of negative value is shown on the second diagram

P(Z<0.49) - P(Z<-0.73) = 0.9879 - 0.2327 = 0.7552 = 75.52%

Question 2
Probability between X=2.11 and X=3.5

z-score for X=2.11
z= \frac{2.11-3.1}{0.41}=-2.41

z-score for X=3.5
z= \frac{3.5-3.1}{0.41} =0.98

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P(Z<0.98) - P(Z<-2.41) = 0.8365 - 0.0080 = 0.8285 = 82.85%

Question 3
Probability less than X=2.96

z-score of X=2.96
z= \frac{2.96-3.1}{0.41}=-0.34
P(Z<-0.34) = 0.3669 = 36.69%

Question 4
Probability more than X=3.4
z= \frac{3.4-3.1}{0.41}=0.73
P(Z>0.73) = 1 - P(Z<0.73) = 1-0.7673=0.2327 = 23.27%



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