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masya89 [10]
2 years ago
8

Winston-Salem is halfway between Boone and Raleigh. Burlington is halfway between Winston- Salem and Raleigh. If Boone is locate

d at the coordinates (-1,3) and Raleigh is at (-5, 9), what are the coordinates of Burlington?
Mathematics
1 answer:
loris [4]2 years ago
7 0

Answer:

The answer is (-4, 15/2)

Step-by-step explanation:

Let the Boone be x, Winston-Salem be y, Raleigh be z and Burlington be m.

We are given that Winston-Salem is halfway between Boone and Raleigh. Burlington is halfway between Winston- Salem and Raleigh.

If Boone is located at the coordinates (-1,3) and Raleigh is at (-5, 9).

We will use Midpoint Formula

( \frac{x _{1} + x _{2}}{2} , \frac{y _{1} + y _{2}}{2} ) \\

Where,

x₁ = (-1) and x₂ = (-5)

y₁ = 3 and y₂ = 9

Now, We will find Co-ordinates of y i.e., Winston-Salem.

So,

( \frac{( - 1) + ( - 5)}{2} , \frac{3 + 9}{2} ) \\

( \frac{( - 1 - 5)}{2} , \frac{12}{2} ) \\

( \frac{ - 6}{2} , \frac{12}{2} ) \\

( - 3,6)

Here, The coordinates of y i.e., Winston-Salem is (-3, 6).

Now, We will find Co-ordinates of m i.e., Burlington.

So,

Again, Using of Midpoint Formula;

Where,

x₁ = (-3) and x₂ = (-5)

y₁ = 6 and y₂ = 9

So,

( \frac{( - 3) + ( - 5)}{2} , \frac{6 + 9}{2} ) \\

( \frac{( - 3 - 5)}{2} , \frac{15}{2} ) \\

( \frac{( -8)}{2} , \frac{15}{2} ) \\

( - 4  , \frac{15}{2} ) \\

Thus, The coordinates of Burlington is (-4, 15/2).

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ANSWER:

1) 25.70 cm 2) 30.84 cm 3) 10.71 km 4) 1.07 km 5) 6.71 cm 6) 10.07  mm

EXPLANATION:

<em>1. Know that the circumference formula for a full circle is:</em>

C = 2\pi r

The value of pi (\pi) = 3.14

The radius (r) will be given in the diagrams.

<em>2. Now we can figure out the perimeters. </em>

<u>Shape One: Semi-circle</u>

C = 2 x 3.14 x 5

C = 31.4 cm

Divide the circumference by 2 because it is a semi-circle. Then add 10 cm to this (because the flat side is 10 cm).

P = \frac{31.4}{2} +10

P = 25.7 cm ≈ 25.70 cm

<u>Shape Two: Semi-circle</u>

C = 2 x 3.14 x 6 (the picture shows the diameter so we need to half that to get the radius)

C = 37.68 cm

Divide the circumference by 2 because it is a semi-circle. Then add 12 cm to this (because the flat side is 12 cm).

P = \frac{37.68}{2}+12

P = 30.84 cm

<u>Shape Three: Quadrant</u>

C = 2 x 3.14 x 3

C = 18.84 km

Divide the circumference by 4 because it is a quadrant. Then add 6 km to this (because the two flat sides are 3 km each and so it is 6 km total).

P = \frac{18.84}{4} +6

P = 10.71 km

<u>Shape Four: Quadrant</u>

C = 2 x 3.14 x 0.3

C = 1.884 km

Divide the circumference by 4 because it is a quadrant. Then add 0.6 to this (because the two flat sides are 0.3 km each and so it is 0.6 km total).

P = \frac{1.884}{4} + 0.6

P = 1.071 km ≈ 1.07 km

<u>Shape Five</u>

C = 2 x 3.14 x 1

C = 6.28 cm

For this shape, we need to subtract the circumference of the missing sector from the circumference of the full circle to obtain the circumference for this shape. So, the circumference for the shape would be:

C =  6.28 - \frac{6.28}{4}

C = 6.28 - 1.57

C = 4.71 cm

Then add the flat sides (1 cm + 1 cm = 2 cm) to this circumference to get the perimeter.

P = 4.71 + 2

P = 6.71 cm

<u>Shape Six</u>

C = 2 x 3.14 x 1.5 (Divide the 3 mm diameter by 2 to get the radius)

C = 9.42 cm

Do the same thing you did for Shape 5.

C = 9.42 - \frac{9.42}{4}

C = 7.065 mm

Then add the flat sides (1.5 + 1.5 = 3) to this circumference.

P = 7.065 + 3

P = 10.065 mm ≈ 10.07 mm

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