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andriy [413]
3 years ago
12

A chemistry student needs 50.00g of acetic acid for an experiment. He has available 450. g of a 31.9%w solution of acetic acid i

n ethanol. Calculate the mass of solution the student should use
Chemistry
1 answer:
Yuliya22 [10]3 years ago
7 0

Answer:

The student should use 156.7 g of solution

Explanation:

31.9 %w solution of acetic acid in ethanol means 100 g of solution contains 31.9 g of acetic acid.

So, 450. g of solution contains (\frac{31.9\times 450.}{100})g of acetic acid or 143.55 g of acetic acid

Alternatively, 143.55 g of acetic acid is present in 450. g of solution

So, 50.00 g of acetic acid is present in (\frac{450.\times 50.00}{143.55})g solution or 156.7 g of solution

Hence the student should use 156.7 g of solution

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Answer:- 1337 g

Solution:- For mathematical operations we use PEMDAS. P stands for parenthesis off, E stands for exponents, M stands for multiplication, D stands for division, A stands for addition and S stands for subtraction. All the mathematical operations are done in this sequence.

What we have given in the problem is, 1210.0 g + 157.22 g - 30. g

Here we have addition and subtraction. As per the law, we will do addition first. In addition and subtraction we go with least number of decimal places.

1210.0 has one decimal place where as 157.22 has two decimal places, since the first number has least decimal places(one decimal place), the answer should also have only one decimal place.

1210.0 g + 157.22 g = 1367.2 g

Now, we will do subtraction. 30. does not have any decimal place and so on subtraction the final answer must not have any decimal places.

1367.2 g - 30. g = 1337 g

So, the final answer is 1337 g.

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