Here’s a simplified explanation.
The <em>protons</em> in the nucleus <em>repel each other</em>. The <em>neutrons provide the “glue”</em> that holds the nucleus together and prevents it from flying apart.
The “glue” is the strong nuclear force. It is strong but extremely short range. It falls off extremely rapidly as the p-n distance increases.
A <em>neon atom</em> has 10 protons. There are three stable isotopes, with 10, 11, and 12 neutrons.
With fewer than 10 protons, the glue is not strong enough to hold the nucleus together.
If there are more than 12 neutrons, the average p-n distance is great enough that the glue has again become too weak.
<em>Gold</em> has one stable isotope. It contains 79 protons and 118 neutrons.
If there are fewer than 118 neutrons, the proton repulsions will be too strong for the strong force. If there are more than 118 neutrons, the average p-n distance will be large enough that the glue will again be too weak to hold the nucleus toge
ther.
One experimental property directly related to the strength of intermolecular forces is the boiling point of a substance.
In the liquid state, the intermolecular forces play a large role in the behavior of the substance. If the boiling point is low, this indicates weak forces such as Van der Waal's forces. On the other hand, a high boiling point indicates strong intermolecular forces such as hydrogen bonds.
Answer:
Redox type
Explanation:
The reaction is:
2Cr + 3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃
2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.
If we see oxidation state, we see that chromium changes from 0 to +3
Iron changed the oxidation state from +2 to 0
Remember that elements at ground state has 0, as oxidation state.
Iron is being reduced while chromium is oxidized. Then, the half reactions are:
Fe²⁺ + 2e⁻ ⇄ Fe (Reduction)
Cr ⇄ Cr³⁺ + 3e⁻ (Oxidation)
When an element is being reduced, while another is being oxidized, we are in prescence of a redox reaction.
Why do molecules combined into chains?
There you go , This is my work i have did on that subject area
