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3 years ago

A certain atom has a nucleus containing six protons and eight neutrons and has six electrons orbiting the nucleus

Chemistry

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

The answer is a carbon isotope.

Explanation:

Carbon has 6 protons and electrons so the atom is neutral.

However it is a carbon isotope because it has more neutrons than protons so be aware of that

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SUBMIT

shutvik [7]

Answer:

i guess its the red wave so A

6 0

2 years ago

A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, w

taurus [48]

Answer:

15.38 g is the mass for M in the 329 g of sample

Explanation:

Mineral's formula: MS

Our sample weighs 44.9 g

Mass of M: 2.1 g

Our new sample weighs 329 g

We may solve this by a rule of three:

44.9 g of sample contain 2.1 g of M

329 g of sample will contain (329 . 2.1) / 44.9 = 15.38 g

5 0

2 years ago

Read 2 more answers

Suppose hydrochloric acid reacts with potassium sulfite yielding water, sulfur dioxide, and potassium chloride. Suppose 4 moles

anzhelika [568]

Answer:

128 grams of sulfur dioxide are produced.

Explanation:

$2HCl+K_2SO_3\rightarrow SO_2+2KCl+H_2O$

Moles of HCl = 4 moles

According to reaction, 2 moles of HCl gives 1 mole of sulfur dioxide gas.

Then 4 moles of HCl will give:

$\frac{1}{2}\times 4 moles=2 moles$ of sulfur dioxide gas.

Mass of sulfur dioxide gas = 2 mol × 64 g/mol = 128 g

128 grams of sulfur dioxide are produced.

4 0

2 years ago

Even though lead is toxic, lead compounds were used in ancient times as white pigments in cosmetics. What is the percentage of l

Gekata [30.6K]

<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %

<u>Explanation:</u>

The given chemical formula of lead (IV) carbonate is $Pb(CO_3)_2$

To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

$\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100$

Mass of lead = (1 × 207.2) = 207.2 g

Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

Putting values in above equation, we get:

$\text{Mass percent of lead}=\frac{207.2g}{327.2g}\times 0100=63.32\%$

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %

4 0

2 years ago

Calculate the Kc for the following reaction if an initial reaction mixture of 0.500 mole of CO and 1.500 mole of H2 in a 5.00 li

Temka [501]

Answer:

can you be more clear with your question :

7 0

1 year ago