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kobusy [5.1K]
3 years ago
8

8/9divided by 1 1/3

Mathematics
1 answer:
Katena32 [7]3 years ago
3 0

Answer:

Step-by-step explanation:8/9  divided by 11/3

8/9*3/11

<h2>24/99</h2>

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4⁄8 + ¼ = ? What would the answer be?
Lorico [155]
3/4. 4/8= 2/4. so 1/4+2/4=3/4
3 0
3 years ago
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There are 40 students playing dodge ball in a high school gym that is 100 feet long by 60 feet wide. There are 12,000 balls avai
shutvik [7]

Answer:

I've never done this before, but if it is balls per square foot, then i can figure it out. It is 2 balls per square foot

Step-by-step explanation:

If the gym is 100 ft by 60 ft, it will be 6,000 square ft. Since there are 12,000 balls, you divide it by 6,000 (12,000/6,000), which is 2, so it would be 2 balls per square foot

5 0
3 years ago
Math homework please help
Viktor [21]

the first on is -42

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3 years ago
Devon records 4 hours of reality shows on her DVR she records comedy shows for 3/8 of that amount of time. Devon watches all the
Alenkinab [10]

The number of half-hour sittings needed to watch all the shows by Devon is 11

<u>Solution:</u>

Given, Devon records 4 hours of reality shows on her DVR  

she records comedy shows for 3/8 of that amount of time.  

\rightarrow \frac{3}{8} \text { of } 4 \text { hours } \rightarrow \frac{3}{8} \times 4 \rightarrow \frac{3}{2} \text { hours }

Devon watches all the reality and comedy shows in half-hour sittings.

We have to find the number of half-hour sittings needed to watch all the shows

Now, number of half hour sittings is given as

=\frac{\text { total time of videos }}{\text { time for hlaf hour sitting }}

\begin{array}{l}{=\frac{4 \text { hours for reality shows }+\frac{3}{2} \text { hours for comedy shows }}{\frac{1}{2} \text { hours for each sitting }}} \\\\ {=\frac{4+\frac{3}{2}}{\frac{1}{2}}=\frac{\frac{8+3}{2}}{\frac{1}{2}}=\frac{\frac{11}{2}}{\frac{1}{2}}=\frac{11}{2} \times \frac{2}{1}=11}\end{array}

Hence Devon needs 11 sittings

3 0
3 years ago
Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
dolphi86 [110]

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

7 0
3 years ago
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