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Nonamiya [84]
3 years ago
5

Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5

Mathematics
1 answer:
dolphi86 [110]3 years ago
7 0

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

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3 years ago
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Answer:

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Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

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The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

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\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

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