Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
1 answer:
Answer:
30
Step-by-step explanation
<h3>In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in all expressions
as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8
likewise for (x-4) we shall take maximum of 2 and 5 which is 5
so our expression for Least common multiple will be
2X3X5 X
30
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Answer:
b.g(x)=+3
Step-by-step explanation:
If two graphs have the same shape and you only want to change one's y intercept, you just have to add or subtract the number at which you want the graph to intercept the y axis from the equation
One way to do it is with calculus. The distance between any point 
on the line to the origin is given by
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and 
attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.
Solving for
, you find a critical point of 
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Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.
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The minimum distance is then
Now, both
Solving for
Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.
You have
so indeed, a minimum occurs at
The minimum distance is then