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lana [24]
4 years ago
12

Please I NEED HELP ASAP Graph the system of equations 2x+y=5; 14+7y=35

Mathematics
2 answers:
xxMikexx [17]4 years ago
8 0

To do the first one, we need to find two points where the coordinates are integers (just for simplicity). First, notice that when x = 0, y is 5, and when x = 1, y = 3. So, graph the points (0, 5) and (1, 3) on the coordinate plane and connect them with a line.

For the second one, I assume you meant to put 14x + 7y = 35. So, to simplify things, let's divide  both sides by 7 to get 2x + y = 5. This is the same one! So, we can go back to out previous answer.

If it wasn't 14x + 7y = 35, I will post the graph to 14 + 7y = 35. Divide both sides by 7 to get 2 + y = 5, or y = 3. So, take two points where x is any number and y is 3, and connect these.

Luden [163]4 years ago
5 0
You have to put it in Y=MX+B form, so that mean you subtract the 2x in the first equation and move it to the other side of the equal sign so it will look like this Y=2X+5 and for the second equation you do the same thing and thats your answer
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7 0
3 years ago
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Niamh runs 6 km in 30-minutes what is the average speed in km h
SIZIF [17.4K]

Step-by-step explanation:

Speed = Distance / Time

given distance = 6km

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4 0
3 years ago
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Step One: We need to convert 1/3 and 1/8 so both have the same denominator, so we need to find the a number that is able to be multiply by 3 and 8 for the process.

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3 years ago
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3 years ago
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ankoles [38]

Answer:

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Step-by-step explanation:

Given 20x^{2}-30=4x

    Subtract 4x from both sides

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Since we can factor out 2 from whole equation, let's factor out 2.

         2(10x^{2}-2x-15)=0

Divide with 2 on both sides

         10x^{2}-2x-15=0

We got the quadratic equation, we can solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}

x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}

x=\frac{2\pm\sqrt{604} }{20}

x=\frac{2\pm2\sqrt{151}}{20}

x=1.3288or-1.1288


8 0
3 years ago
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