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ruslelena [56]
3 years ago
14

If the distribution is really N ( 5.43 , 0.54 ) , N(5.43,0.54), what proportion of observations would be less than 5.05 ? 5.05?

(Enter your answer rounded to four decimal places.)
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

P(X

And we can use the following excel code to find the answer: "=NORM.DIST(-0.704,0,1,TRUE)"

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable of interest for a population, and for this case we know the distribution for X is given by:

X \sim N(5.43,0.54)  

Where \mu=5.43 and \sigma=0.54

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability on this way:

P(Z

And we can use the following excel code to find the answer: "=NORM.DIST(-0.704,0,1,TRUE)"

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Let C be the center of the circle. The measure of arc VSU is 2+114x, so the measure of the minor arc VU is 360-(2+114x)=358-114x. The central angle VCU also has measure 358-114x.

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