Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
Answer:
(x,y)=(-2,-5)
Step-by-step explanation:
y=1/2x-4
y=-2x-9
(y=) 1/2x-4=-2x-9
1/2x +2x=-9+4
1/2x +4/2x=-5
5/2x=-5
5x=-5*2
5x=-10
x=-2
x=-2
y=-2x-9=-2*(-2)-9=4-9=-5
(x,y)=(-2,-5)
Answer:
a) G
b) C
Step-by-step explanation:
Answer:
x = 2
Step-by-step explanation:
Answer:
the cat weighs 21 pounds.
the dog weighs 43 pounds
Step-by-step explanation:
dog = 3x-20 = x + 22
cat = x
3x-20 = x+22
3x = x+42 (add 20 to both sides)
2x = 42 (subtract x from both sides)
x = 21