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Let x represent the side length of the square end, and let d represent the dimension that is the sum of length and girth. Then the volume V is given by
V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
dV/dx = 0 = -12x² +2dx
0 = -2x(6x -d)
This has solutions
x = 0, x = d/6
a) The largest possible volume is
(d/6)²(d -4d/6) = 2(d/6)³
= 2(108 in/6)³ = 11,664 in³
b) The dimensions of the package with largest volume are
d/6 = 18 inches square by
d -4d/6 = d/3 = 36 inches long
V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
dV/dx = 0 = -12x² +2dx
0 = -2x(6x -d)
This has solutions
x = 0, x = d/6
a) The largest possible volume is
(d/6)²(d -4d/6) = 2(d/6)³
= 2(108 in/6)³ = 11,664 in³
b) The dimensions of the package with largest volume are
d/6 = 18 inches square by
d -4d/6 = d/3 = 36 inches long
Answer:
-15
Step-by-step explanation:
Given is a polynomial in x
We have to find the remainder when the above polynomial is divided by x+5
Remainder theorem says that f(x) gives remainder R when divided by polynomial x-a means f(a) = R
Applying the above theorem we can say that value of the function when x =-5
= Remainder when f is divided by x+5
= F(-5)
Substitute the value of -5 in place of x
= (-5)^4 + 12(-5)^3 + 30(-5)^2 - 12(-5) + 70
= 625-1500+750+60+70
= 5
Hence answer is 5