Answer:
linkage with approximately 33 map units between the two gene loci
Explanation:
If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:
AaBb = 106 = Parental
aabb = 94 = Parental
Aabb = 48 = Recombinant
aaBb = 52 = Recombinant
Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %
1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.
Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci
So first transcription takes place which is a RNA that translates DNA Template. So an example would be DNA has AGCGTCAATCTA this will be translated into UCGCAGUUAGAU
Then this message is send off to become a protein with the MRNA which then comes Translation which is the process of converting UCGCAGUUAGAU into a protein and the way it’s done is by this message going through a ribosome and gets translated by TRNA that brings amino acids together to form codons and create your protein.
The answer would be about 18.
<span>Christmas trees give, in fact, a lot of oxygen and in return they consume a lot of carbon dioxide.
</span><span>The oxygen produced by each tree depends on several factors, but there is a estimative. In about 1 acre of land, there are enough trees to produce the oxygen necessary for 18 people to breath during a whole year!
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