1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
2 years ago
5

726,000 scientific notation​

Mathematics
2 answers:
muminat2 years ago
7 0

Answer:

7.26 X 10^5

Step-by-step explanation:

Move the decimal 5 times.

il63 [147K]2 years ago
3 0

Answer:

7.26000 × 10^{5}  

I hope this helps!

You might be interested in
Expand this expression (x-y)²<br>​
pochemuha

Answer:

x^2 - 2xy + y^2.

Step-by-step explanation:

(x - y)^2

= (x - y)(x - y)

= x(x -y) - y(x - y)

= x^2 - xy - xy + y^2

= x^2 - 2xy + y^2.

8 0
2 years ago
HELP PLEASEEEEE URGENT
gregori [183]

Answer:

5

Step-by-step explanation:

1) Solve for the slope(m):

(y2-y1) / (x2-x1)

pick any

(-3 - (-5) )/ (1 - 0)

(-3 + 5) / (1 - 0)

2/1 = 2

2) b(intercept) value is found when x = 0:

x = 0, y = -5,

b = y

b = -5

3) Plug it in:

y = mx + b

y = 2x - 5

4) when the value is 5, x = 5:

y = 2x - 5

y = 2(5) - 5

y = 10 -5 = 5

6 0
3 years ago
Solve For Each Variable.
bixtya [17]

The first equation given 6=1-2n+5

We have to add 1 and 5 to the right side first. We will get,

6= 6 - 2n

To get rid of 6 from the right side we have to subtract 6 from both sides.

6-6 = 6-6-2n

6-6 = -2n

0=-2n

To find n we have to move -2 to the other side by dividing both side by -2.

0/-2 = -2n/-2

0= n

n=0

So we have got the required answer for the first question.

The solution is n = 0.

The second equation given,

8x-2 = -9+7x

First we have to move 7x to the left side by subtracting it from both sides.

8x-7x-2 = -9+7x-7x

8x-7x-2 = -9

x-2 = -9

Now we have to move -2 to the right side by adding 2 to both sides.

x-2+2 = -9+2

x = -9+2

x = -7

We have got the required answer for the second question.

The solution is x = -7.

The third equation given,

-8 = -(x+4)

We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,

8=x+4

Now we have to move 4 to left side by subtracting it from both sides.

8-4 = x+4-4

8-4 = x

4=x

x = 4

So we have got the required answer .

The solution is x = 4.

3 0
2 years ago
NEED HELP ASAP PLEASE!!
qwelly [4]

Option D:

$y=\frac{5x-2}{x}

Solution:

Given function:

$y=\frac{-2}{x-5}

To find the inverse of the function.

<u>Inverse of a function:</u>

<em>If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back to x.</em>

$y=\frac{-2}{x-5}

Interchange the variables x and y.

$x=\frac{-2}{y-5}

Now, solve for y.

Multiply both sides by (y - 5).

$x(y-5)=-\frac{2}{y-5}(y-5)

Cancel the common factors, we get

x(y-5)=-2

Divide by x on both sides.

$y-5=-\frac{2}{x}

Add 5 on both sides.

$y=-\frac{2}{x}+5

$y=-\frac{2}{x}+\frac{5}{1}

To make the denominator same, multiply the 2nd term by \frac{x}{x}.

$y=-\frac{2}{x}+\frac{5x}{x}

$y=\frac{-2+5x}{x}

$y=\frac{5x-2}{x}

Option D is the correct answer.

8 0
2 years ago
Nine fewer than half a number is 5 more than four times the number define a varuble
Amanda [17]

5/2x-9+4x

the variable is x

4 0
2 years ago
Other questions:
  • Evaluate lal - Ibl, given a = 5, b = -3, and c = -2.<br>a. 2 b. 3 c. 7 d. 8​
    15·1 answer
  • What is 9 x any number 1 through 10
    11·2 answers
  • When both parties discuss the terms of a contract, they are ____
    15·2 answers
  • Help me cuz yah gurl gotta test UwU
    10·1 answer
  • Find the slope of the line that passes through (1, 15) (10, 8)
    10·2 answers
  • What type of function does the table show?*
    11·1 answer
  • Hlw to find ghe area of a parallelogram
    11·2 answers
  • Find the are of the blue shaded region.
    14·2 answers
  • What is the area of this figure? <br>​
    8·1 answer
  • HELPPPP WITH MATHH HOMEWORKK PLSSS
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!