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3 years ago

How many solutions exist for 2|x − 1| = 8?

1 answer:

4 0

Two solutions exist,
2(x - 1) = 8
2x - 2 = 8
2x = 10
x = 5
&
2(x + 1) = 8
2x + 2 = 8
2x = 6
x = 3

the two solutions are 5 and 3

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In the class of 40 students,18 passed mathematics,19 passed account,16 passed economics,5 passed mathematics and accounts only ,

Alexus [3.1K]

Answer:

A) 4 students

B) 32.5%

C) 19/40

Step-by-step explanation:

Using set notation to solve the problem with universal set n(U) = 40

Let n(A) be the number of students that pass account

n(E) be the number of students that pass economics

n(M) be the number of students that pass mathematics

n(AUEUM)' be number of students that failed in all the 3 subjects.

n(AUEUM) be number of students that pass in all the 3 subjects.

n(U) = n(AUEUM)+ n(AUEUM)'

Find the remaining solution in the attachment

4 0

3 years ago

A circle has a radius of 5p6q3 cm. The area of the circle can be found using the formula A = πr2. What is the area of this circl

Tamiku [17]

Answer:

25p^12q^6πcm²

Step-by-step explanation:

Given the area of the circle expressed as;

A = πr^2

Given

r = 5p^6q^3 cm

Substitute into the formula

A = π(5p^6q^3 )²

A = π(25p^12q^6)

A = 25p^12q^6πcm²

hence the area of this circle in square centimeters is 25p^12q^6πcm²

4 0

3 years ago

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

yawa3891 [41]

Answer:

The probability is 0.003

Step-by-step explanation:

We know that the average $\mu$ is:

$\mu=500$

The standard deviation $\sigma$ is:

$\sigma=100$

The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

We seek to find

$P(x800)$

For P(x>800) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{800-500}{100}$

$Z=3$

The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x>800)=0.15\%$

For P(x<200) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{200-500}{100}$

$Z=-3$

The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x$