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3 years ago

Help please!!!!!!!!!

Mathematics

1 answer:

Sophie [7]3 years ago

5 0

Answer:

I believe its the second one but i could be wrong

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What is the surface area of the pyramid?

mihalych1998 [28]

Answer:

Step-by-step explanation:

square= lw

triangle= 1/2lw

s=9

triangle=15 divided by 2 times 4=30

you add 30 + 9 which will give you 39

3 0

3 years ago

Read 2 more answers

Solve for a.

MrMuchimi

The answer has to be -9 because -9 + -4 is equal to -9 - 4, and that equals -13.

6 0

4 years ago

Read 2 more answers

Find the error and explain why its wrong

UNO [17]

Answer:

The last part.

Step-by-step explanation:

The error is only at the last part. Basically the answer part.

The answer should be —

$13 \sqrt{5}$

We don't multiply the square roots when adding or subtracting. That'd contradict the rules.

Here, we let the square root of five as x-term.

$\sqrt{5} = x$

$4 \sqrt{5} + 9 \sqrt{5} = 4x + 9x$

As we add up, we would get 13x. Thrn we convert x-term back to square root of five.

The answer would be —

$13x \\ x = \sqrt{5} \\ 13 \sqrt{5}$

Remember that we don't multiply the square roots when adding or subtracting.

5 0

3 years ago

Find the distance CD rounded to the nearest tenth. C=(5,6) and D (2,2) CD=

navik [9.2K]

Use the distance formula to find the distance between points C (5,6) and D (2,2).

d= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

Plug the corresponding values in to the equation.

d= $\sqrt{(2-5)^2+(2-6)^2}$

Then simplify the rest of the equation.

d= $\sqrt{(-3)^2+(-4)^2}$

d= $\sqrt{9+16}$

d= $\sqrt{25}$

d= $5$

The distance of the two points CD is 5.

7 0

4 years ago

Identify each function that has a remainder of -3 when divided x+6

Sergeu [11.5K]

Answer:

Step-by-step explanation:

According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.

So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.

For A:

$x^5 + 2x^2 - 30x + 30\\=(-6)^5 + 2(-6)^2 - 30(-6) + 30\\=-7494$

For B:

$x^4 + 4x^3 - 21x^2 - 53x + 12\\=(-6)^4 + 4(-6)^3 - 21(-6)^2 - 53(-6) + 12\\=6$

For C:

$x^3 - 10x^2 - 7\\=(-6)^3 - 10(-6)^2 - 7\\=-583$

For D:

$x^4 + 6x^3 - 10x - 63\\=(-6)^4 + 6(-6)^3 - 10(-6) - 63\\=-3$

The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.

5 0

3 years ago