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3 years ago

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A certain game involves tossing 3 fair coins, and it pays 19 cents for 3 heads, 9 cents for 2 heads, and 3 cents for 1 head. Is

9 cents a fair price to play this game? That is, does the 9 cents cost to play the game fair.

1 answer:

Softa [21]3 years ago

3 0

Idk idk idk idk idk idk idk

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Parking at a large university has become a very big problem. University administrators are interested in determining the average

Oduvanchick [21]

Answer:

The 260 students that are followed.

Step-by-step explanation:

According to the situation explained in the question, the university administration is trying to collect data on the students' parking times to figure out a solution for the parking problem in the university.

After following and collecting data from 260 students, the population of interest to the university administration should be the all 260 students that the data is collected from because population of interest describes a "population" that are being studied and having data collected from them.

I hope this answer helps.

7 0

4 years ago

Rainbow [258]

Answer:

C-5m

Step-by-step explanation:

8 0

3 years ago

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Whats the answer? Ill make u brainliest .

inn [45]

Answer:

I'm not sure but I think it is C.

5 0

3 years ago

If f(x)=3x^2 +1 and g(x)=1-x, what is the value of (f-g)(2)

liraira [26]

$(f-g)(x)=3x^2+1-(1-x)=3x^2+1-1+x=3x^2+x\\\\ (f-g)(2)=3\cdot2^2+2=14$

5 0

3 years ago

One pound of grout is enough to grout a tiled area that is 110 sq. Ft. Alyssa's kitchen counter is made up of two rectangular se

Ratling [72]

Answer:

$(10.3(2.5)+3.1(2))\div 110$

Step-by-step explanation:

$A_1$ = Area of 1st rectangle = $(10.3\times 2.5)\ \text{ft}^2$

$A_2$ = Area of 2nd rectangle = $(3.1\times 2)\ \text{ft}^2$

$1\ \text{pound of grout}=110\ \text{ft}^2$

$\Rightarrow 1\ \text{ft}^2=\dfrac{1}{110}\ \text{pound of grout}$

The number of pounds required for the counter top is

$\text{Total area}\times \text{The amount of grout used in 1 ft}^2$

$=A_1+A_2\times \dfrac{1}{110}=(10.3(2.5)+3.1(2))\times \dfrac{1}{110}\\ =(10.3(2.5)+3.1(2))\div 110$

The required expression is $(10.3(2.5)+3.1(2))\div 110$ .

6 0

3 years ago

Read 2 more answers