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Shtirlitz [24]
3 years ago
5

There are 4 sports stores,9 clothing stores and 6 jewelry stores ina shopping crnter which ratio compares the number of sports s

tores to the total number of stores
Mathematics
1 answer:
Pani-rosa [81]3 years ago
7 0

The ratio is  2 : 9

Step-by-step explanation:

Given:

The number of sports store = 4

The number of clothing store  = 9

The number of jewellery stores = 5

To Find :

The ratio of number of sports stores to the total number of stores

Solution:

The ratio of number of sports stores to the total number of stores

= \frac{\text{number of sports store}}{\text{ Total number of stores}}

The total number of stores =  number of sports store + number of clothing store + number of jewellery store

The total number of stores = 4 + 9 + 5

The total number of stores = 18

Now the ratio is

= \frac{4}{18}   or 4  :  8

The ratio after reduction is

=\frac{2}{9} or 2 : 9  or   2 to 9

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ANSWER

363.6 \: miles
EXPLANATION

We were told that the motorist travelled 250 miles on 11 gallons of gas. This implies that,

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All other things being equal, the motorist should cover more than 250 miles with 16 gallons of gas.

Recall that: If more, less divides.

This implies that,

x =  \frac{250 \times 16}{11}




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Therefore the correct answer is C.

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3 years ago
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IRINA_888 [86]

The area of rhombus is 24 square units.

Step-by-step explanation:

Given,

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Area of rhombus = \frac{6*8}{2}

Area of rhombus = \frac{48}{2}

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The area of rhombus is 24 square units.

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A pumpkin is launched directly upwards at 72 feet per second from a platform 24 feet high. The pumpkins height, h, at time t sec
STALIN [3.7K]

Answer: Maximum height =  105 feet

And, It takes 9/4 seconds to reach that point.

Step-by-step explanation:

Here the given function that shows the height of the pumpkin,

h(t) = -16t^2 + 72t + 24 --------(1)

Where t is the time in second.

Differentiating equation (1) with respect to t,

We get,    h'(t) = -32 t + 72

Again differentiating above equation with respect to t,

We get,   h''(t) = -32

For maximum or minimum,    h'(t) = 0

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And, the maximum value is,

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Answer:


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