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KatRina [158]
2 years ago
14

Can somebody please help!! Its a math equation on my math quiz

Mathematics
2 answers:
fomenos2 years ago
8 0

Answer:

Solving the equation for w we get : \mathbf{w=q\times z+4}

Step-by-step explanation:

We are given the equation: q=\frac{w-4}{z} and we need to solve for w

We need to solve the given equation and find value of w.

We will solve in such a way that, w is on left-side of equation and all other terms are on right-side of the equation.

Solving:

q=\frac{w-4}{z}

Multiply z on both sides

q\times z=\frac{w-4}{z}\times z\\q\times z=w-4

Adding 4 on both sides

q\times z+4=w-4+4\\w=q\times z+4

So, solving the equation for w we get : \mathbf{w=q\times z+4}

CaHeK987 [17]2 years ago
5 0

Answer:

w = q z + 4

Step-by-step explanation:

Solve for  w  by simplifying both sides of the equation, then isolating the variable.

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consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

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x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

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Any number divisible by 5 is divisible by 10 ?
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Answer:

Yes , the number should be even and divisible by 5 and then it can be divisible by 10 as well

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$6000 are invested in a bank account at an interest rate of 10 percent per year.
Licemer1 [7]

The amount for the investment of $6000 will be a.$6369  b. $6090  and c.$6030.

<h3>What is compound interest?</h3>

Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-

A=P[1+\dfrac{r}{n}]^{nt}

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