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KatRina [158]
3 years ago
14

Can somebody please help!! Its a math equation on my math quiz

Mathematics
2 answers:
fomenos3 years ago
8 0

Answer:

Solving the equation for w we get : \mathbf{w=q\times z+4}

Step-by-step explanation:

We are given the equation: q=\frac{w-4}{z} and we need to solve for w

We need to solve the given equation and find value of w.

We will solve in such a way that, w is on left-side of equation and all other terms are on right-side of the equation.

Solving:

q=\frac{w-4}{z}

Multiply z on both sides

q\times z=\frac{w-4}{z}\times z\\q\times z=w-4

Adding 4 on both sides

q\times z+4=w-4+4\\w=q\times z+4

So, solving the equation for w we get : \mathbf{w=q\times z+4}

CaHeK987 [17]3 years ago
5 0

Answer:

w = q z + 4

Step-by-step explanation:

Solve for  w  by simplifying both sides of the equation, then isolating the variable.

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The volume of a cylinder is 4 pi x3 cubic units and its height is x units.
Rzqust [24]

Answer:

2x

Step-by-step explanation:

The volume of a cylinder, V is given by the formula,

V=\pi r^{2}h

Where, r is the radius and h is the height of the cylinder.

Here, V=4\pi x^{3}, h=x. Plug in these values and solve for radius, r.

This gives,

V=\pi r^{2}h\\4\pi x^{3}=\pi r^{2}x\\r^{2}=\frac{4\pi x^{3}}{\pi x}\\r^{2}=4x^{2}\\

Taking square root both sides, we get

\sqrt{r^{2}}=\sqrt{4x^{2}}\\r=2x

Therefore, the radius of the cylinder can be expressed as 2x.

6 0
3 years ago
Find the product. (4m^2 – 5)(4m^2 + 5)
aliya0001 [1]

Answer: 16m^4−25


Step-by-step explanation:

(4m^2−5)(4m^2+5)

=(4m^2+−5)(4m^2+5)

=(4m^2)(4m^2)+(4m^2)(5)+(−5)(4m^2)+(−5)(5)

=16m^4+20m^2−20m^2−25

=16m^4−25

3 0
3 years ago
Mrs. Chin paid a 20 percent tip on the bill for lunch.
dolphi86 [110]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Evaluate 5÷9(F - 32) when f=50
solmaris [256]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
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Hi i would like sum help :)) please help for a brainlist !!!!!!!!!!!!!
Sergio [31]
A. all real numbers for both

Explanation:
Domain is the x-values. Since the graph goes forever horizontally, any x-value is on the graph.
Range is the same but with y-values. If the graph went on further than what the picture shows, then it also would show that every y value is on the graph
hope this helps
5 0
3 years ago
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