Please help asap i will mark branlist please explain both question
1 answer:
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4x + 2y = 8 (1)
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =
y = -x
<span>Thus the gradient of the two equations are different and as such the two lines are not parallel
</span>
B) When two lines are perpendicular, the product of their gradient is -1
p = (-2) * (-1)
p = 2
<span> ∴ the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =
y = -x
<span>Thus the gradient of the two equations are different and as such the two lines are not parallel
</span>
B) When two lines are perpendicular, the product of their gradient is -1
p = (-2) * (-1)
p = 2
<span> ∴ the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
Answer:
C is correct
Step-by-step explanation:
Given: System of linear inequality
First we will draw the graph of system of equation and then see the correct option.
Equation 1:
We will make the table.
x : -2 0 2
y : 1 0 -1
Test Point: (0,4)
0<-2 ( False )
Shaded area away from (0,4)
Equation 2:
We will make the table.
x : -2 0 2
y : -1 3 7
Test Point: (0,4)
4≥3 ( True )
Shaded area towards (0,4)
Please see attachment for graph.
Hence, C is common shaded area (region)
