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Vlada [557]
3 years ago
9

Jackson wants to divide 2/5 pound box of trail mix into smal bags. Each of the bags will hold 1/10 pound of trail mix. How many

bags can he fill?
Mathematics
2 answers:
storchak [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Let x= # of bags he can fill

It is established that:

2/5 -> x # of 1/10 bags

So to find out:

x=\frac{2}{5} /\frac{1}{10} \\\\x=\frac{2}{5} *\frac{10}{1} \\\\x=\frac{2*10}{5*1} \\\\x=\frac{20}{5} \\\\x=4

Jackson can fill 4 bags of trail mix!

Hope this helps!

OLga [1]3 years ago
6 0
Answer: it should be four 4 because 2/5x2=4/10 which is 4 bags
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1 no.ans=10

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3 years ago
Do the measures of center make​ sense? A. Only the mode makes sense since the data is nominal. B. All the measures of center mak
Ray Of Light [21]

Answer:

A. Only the mode makes sense since the data is nominal.

Step-by-step explanation:

Hello!

The objective of the study was to determine if deficiency of carbon dioxide in the soil affects the phenotype of peas.

The variable of study is X: Phenotype of a pea grown in soil with carbon dioxide deficiency.

Possible values of Phenotype codes:

1= smooth-yellow

2= smooth-green

3= wrinkled-yellow

4= wrinkled-green

The absolute frequencies for each phenotype are:

f(1)= 3

f(2)= 4

f(3)= 6

f(4)= 1

n= 14

<u>a) Mean:</u>

X[bar]= (∑xifi)/n= [(1*3)+(2*4)+(3*6)+(4*1)]/14= 33/14= 2.357= 2.36

The average value is always within range of definition of the variable but it does not necessarily correspond to an observation.

<u>b) Median:</u>

To determine the value that corresponds to the median you have to calculate its position:

For even samples the position is:

PosMe= n/2= 14/2= 7

Then you have to arrange the data from least to greatest, in this case, starting from the first category, you have to determine where the seventh observation is within the observed absolute frequencies. The phenotype that corresponds to the 7th observation is 2= smooth-green.

Me= 2= smooth-green.

<u>c) Mode:</u>

The mode corresponds to the most observed category/ value of the variable, i.e. the category with the most observations is 3= wrinkled-yellow

Md= 3= wrinkled-yellow

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e)

As you can see the variable is qualitative and categorical. Even if all central tendency measurements can be calculated, truth is that the only one that shows any valuable information regarding the data set is the mode.

I hope this helps!

3 0
3 years ago
Mr. Petersons rectangular garden had a width of 3 meters and an area of 10 square meters. This year he wants to make the garden
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Answer:

Measurements of this years garden are 10 meters and 6 metres.

Step-by-step explanation:

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Area of a rectangular garden = 10 square meters

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10 = length × 3

Length = \frac{10}{3} meters

Mr. Petersons wants to make the garden three times as long and two times as wide.

New length = 3 (length) = 3(\frac{10}{3} )=10 meters

New breadth = 2(width) = 2(3) = 6 meters.

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Measurements of this years garden are 10 meters and 6 metres.

8 0
3 years ago
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Brilliant_brown [7]

Answer:

Step-by-step explanation:

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cosC=\frac{adjacent}{hypotenuse}\\\\cosC=\frac{15}{17}

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Hello : 
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