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gogolik [260]
3 years ago
10

if you are looking to determine the range of the following set of numbers which number would you take as the smallest number 2,6

,-1,14,-5,18,3
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
7 0
-5 is the answer because -5 is the lowest number on the number
morpeh [17]3 years ago
3 0
-5 is the smallest. I will put them in order for you (smallest to greatest) -5, -1, 2, 3, 6, 14, 18
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Answer:

each unit being divided into smaller parts

Step-by-step explanation:

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Answer:

y=3x-21

Step-by-step explanation:

a line is parallel if the slopes of the lines are the same

so that means that out line should look something like this

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then, we use our point given to find b

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the equation of out line is y=3x-21

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State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

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Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

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Machine M can used total time= 6hours

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According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
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Mademuasel [1]

If the position at time <em>t</em> is

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<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)

<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)

<em>v</em> (ave) ≈ 12.006 m/s

6 0
2 years ago
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