We define the probability of a particular event occurring as:

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.
Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:
(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5
So, we have

probability of rolling at least one 5.
Answer:
24,192.
Step-by-step explanation:
The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.
The number of permutations of the other 4 numbers is 9P4
= 9! / (9-4)!
= 3024
Now we multiply by the 8:
3024 * 8
= 24,192.
Answer:
12 x -7 = -84 12 + (-7) = 5
Step-by-step explanation:
Answer:
- 8+w/4
- Putting w = 16
- 8+16/4
- (32+16)/4
- = 48/4
- = 12
Step-by-step explanation:
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