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jenyasd209 [6]
3 years ago
9

1 A high school talent show lasted a total of t minutes. There were 2 intermissions that were each the length of 8 the talent sh

ow. Which function can be used to find the number of minutes the talent show lasted, not including intermissions?​
Mathematics
1 answer:
Sophie [7]3 years ago
4 0

Answer:

I think f(t)=1/4t

Step-by-step explanation:

Because of you multiply 1/8 times 2, it gives you 1/4. Not 100% sure tho

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Gwen, Tristan, and Keith like to work out at the gym. They each have an app on their phone that estimates the calories they burn
aleksandrvk [35]

Answer:

Part A:

Gwen has already burned 100 calories when Tristan and Keith started, and he continues to burn 10 calories per minute. The equation for Gwen is

y = 100 + 10x

Part B:

Tristan is burning 125 calories every 10 minutes. His burning calories rate is 12.5 calories per minute. The equation for Tristan is

y = 12.5x

Part C:

Keith is burning 300 calories in 30 minutes. His rate per minute is 10 calories per minute. The equation for Keith is

y = 10x

Part D:

Just follow the instructions and do the thing for the app. You can then answer the questions it is very easy.

Part E:

Do the same for E after you do Part D.

Step-by-step explanation:

Hope it helps!

6 0
3 years ago
Read 2 more answers
n engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that
BartSMP [9]

Answer:

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the Population (μ) = 5.4</em>

<em>Given sample size 'n' = 9</em>

<em>Mean of the sample (x⁻) = 5.7</em>

<em>Standard deviation of the sample (s) = 0.81</em>

<u><em>Step(ii):-</em></u>

<em>Null Hypothesis: H₀:</em>  The engineer designed the valve such that it would produce a mean pressure of 5.4

H₀: μ = 5.4

<em>Alternative Hypothesis : H₁:</em>  μ ≠ 5.4

Level of significance = 0.025

Test statistic

            t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

           t = \frac{5.7 -5.4}{\frac{0.81}{\sqrt{9} } }

         t = 1.11

<em>Degrees of freedom </em>

<em>ν = n-1 = 9-1 =8</em>

t₀.₀₁₅ , ₈  = 2.89

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

<em></em>

<em />

7 0
3 years ago
Can u help me plz ?
egoroff_w [7]

Step-by-step explanation:

Can you please tell me on wht you need help with so I can see if I can help you

8 0
3 years ago
Find the greatest possible error of <br> 14.3 m
guajiro [1.7K]
You can make an error by not adding a zero to it and you can be confused.
6 0
3 years ago
Will Mark brainiest!!!!
Yakvenalex [24]

Answer:

<em>1. 1.55π,</em>

<em>2. 16π,</em>

<em>3. 2.45π,</em>

<em>4. ( About ) 5.56π,</em>

<em>5. 13.7π</em>

<em>6. ( About ) 1.78π</em>

Step-by-step explanation:

1. Let us keep the answer in terms of π, for the simplicity;

Area of Circle ⇒ π * r^2 = π * ( 3 )^2 = 9π,

Degree measure of arc / Degree measure of circle = Area of sector / Area of Circle,

62 / 360 = Area of sector / 9π,

62 * ( 9π ) = 360 * Area of sector,

558π = 360 * Area of sector,

<em>Area of sector; 1.55π</em>

2. Area of Circle ⇒ π * r^2 = π * ( 8 )^2 = 64π,

Area of sector ⇒ 1 / 4 * 64π = 16π,

<em>Area of sector; 16π</em>

3. Area of Circle ⇒ π * r^2 = π * ( 3 )^2 = 9π,

Degree measure of arc / Degree measure of circle = Area of sector / Area of Circle,

98 / 360 = Area of sector / 9π,

98 * ( 9π ) = 360 * Area of sector,

882π = 360 * Area of sector,

<em>Area of sector; 2.45π</em>

4. Area of Circle ⇒ π * r^2 = π * ( 4 )^2 = 16π,

Degree measure of arc / Degree measure of circle = Area of sector / Area of Circle,

125 / 360 = Area of sector / 16π,

125 * ( 16π ) = 360 * Area of sector,

2000π = 360 * Area of sector,

<em>Area of sector; ( About ) 5.56π</em>

5. Area of Circle ⇒ π * r^2 = π * ( 6 )^2 = 36π,

Degree measure of arc / Degree measure of circle = Area of sector / Area of Circle,

137 / 360 = Area of sector / 36π,

137 * ( 36π ) = 360 * Area of sector,

4932π = 360 * Area of sector,

<em>Area of sector; 13.7π</em>

6. Area of Circle ⇒ π * r^2 = π * ( 2 )^2 = 4π,

Degree measure of arc / Degree measure of circle = Area of sector / Area of Circle,

160 / 360 = Area of sector / 4π,

160 * ( 4π ) = 360 * Area of sector,

640π = 360 * Area of sector,

<em>Area of sector; ( About ) 1.78π</em>

7 0
3 years ago
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