X^2-5x-14
x^2+2x-7x-14
x(x+2)-7(x+2)
(x-7)(x+2)
So (x-7) and (x+2) are factors of x^2-5x-14
A15,15,15 B from the top15,1,45,3,15 C 30,2,30,2,15
Answer:
2, 120 degrees
Step-by-step explanation:
The first step in finding the polar form is finding the modulus, r
r= sqrt( x^2 + y^2)
r = sqrt( (-1)^2 + sqrt(3)^2)
r = sqrt(1+3)
r= sqrt(4)
r =2
The next step is finding the angle
theta = arctan (y/x)
theta = arctan (sqrt(3)/-1))
theta = arctan (-sqrt(3))
theta = -60
The point (-1, sqrt(3)) is in the 2nd quadrant, but our angle is in the 4th quadrant, so we add 180 degrees
theta = -60 + 180 = 120
theta = 120 degrees
1)a^7/a^4
=a^[7-4]
=a³
2) r²s⁴t/r²st³
=s⁴-¹.t¹-³
=s³.t-²
=s³/t²
3)3x^6/18x
=x^5/6