Question

What is the vertex form of the equation Y=-x^2-12x-4 Please show all the steps

Answer 1

Answer:

              $\boxed{\bold{y=-(x+6)^2+32}}$

Step-by-step explanation:

$y=-x^2-12x-4\\\\y=-(x^2+12x)-4\\\\y=-(\underline{x^2+2\cdot x\cdot6+6^2}-6^2)-4\\\\y=-\left[(x+6)^2-36\right]-4\\\\y=-(x+6)^2+36-4\\\\\bold{\underline{y=-(x+6)^2+32}}$