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Anton [14]
3 years ago
5

What is the vertex form of the equation Y=-x^2-12x-4 Please show all the steps

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer:

              \boxed{\bold{y=-(x+6)^2+32}}

Step-by-step explanation:

y=-x^2-12x-4\\\\y=-(x^2+12x)-4\\\\y=-(\underline{x^2+2\cdot x\cdot6+6^2}-6^2)-4\\\\y=-\left[(x+6)^2-36\right]-4\\\\y=-(x+6)^2+36-4\\\\\bold{\underline{y=-(x+6)^2+32}}

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Write the following inequality in slope intercept form. -6+2y less than or equal to 42
lisabon 2012 [21]
The slope intercept of a line is given by y=mx+c, where:
m=slope, c=y-intercept. 
Thus the slope-intercept form of our equation will be:
-6+2y≤42
adding 6 in both sides we get:
-6+6+2y≤42+6
2y≤6
dividing both sides by 2 we get:
(2y)/2≤6/2
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the answer is y≤3
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If you do long division of the numerator and nominator, if the remainder is 0, the decimal form is terminating. If the remainder is non-zero, it will be a repeating decimal...

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3 years ago
Solve for x<br> 3x + 2 = 19
AnnyKZ [126]

Answer:

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If (x) and f-1(x) are inverse functions of each other and f(X) =2X+5 what is f-1(8)
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