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Snezhnost [94]
3 years ago
7

The degree of the polynomial function f(x) is 3. The roots of the equation f(x)=0 are −4 , 0, and 2. Which graph could be the gr

aph of f(x) ?

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Just took the quiz, got it right so here it is.

Hope I could help!

KATRIN_1 [288]3 years ago
5 0

We know that the polynomial function is of degree 3, and that its roots are -4, 0, 2.

With this data we can write a generic equation for the function:

f (x) = bx (x + 4) (x-2)

Since the function is of degree 3 and cuts the axis at x = 0, then it has rotational symmetry with respect to the origin.

The graph of the function can be of two main forms, based on the value of the coefficient b.

If b is positive then the function grows from y = -infinite and cuts the x-axis for the first time in -4. Then it decreases, cuts at x = 0 and begins to grow again cutting the x-axis for the third time at x = 2. and continues to grow until y = infnit


If b is negative, then the function decreases from y = infinity and cuts the x-axis for the first time in -4. Then it grows, cuts at x = 0 and begins to decrease again by cutting the x-axis for the third time at x = 2, and continues to decrease until y = -infnit.


In the attached images the graphs of the function f (x) are shown assuming b = -1 and b = 1

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Step-by-step explanation:

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slope = m = 3

Process

To solve this problem just substitute the values given in the slope-point equation.

Formula

               y - y1 = m(x - x1)

   x1 = 2      y1 = 3

-Substitution

              y - 3 = 3(x - 2)

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             y = 3x - 6 + 3

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3 years ago
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
Bad White [126]

Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = \frac32 meters

\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}

\Rightarrow \frac{radius }{height}=\frac {3}{26}

\Rightarrow radius=\frac {3}{26}\times height   ......(1)

The volume of the cone is   V=\frac13 \pi r^2 h

Now putting r=\frac{3}{26} h

V=\frac13 \pi (\frac3{26}h)^2 h

\Rightarrow V=\frac{3}{676} \pi h^3

Differentiating with respect to t

\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}

\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e \frac{dh}{dt}=17 cm/min

Putting \frac{dh}{dt}=17  

\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17

\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17

             ≈7,113 cubic centimetre per minute

The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

           

   

4 0
4 years ago
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