Question

For the equation given below, evaluate y′ at the point (−2,−1). 3xy−3x−12=0.

Answer 1

Answer:

Y'=3xy-3x-12

Y'=F(-2,-1)=0

Step-by-step explanation:

The function of the equation at the point (-2,-1)

is where the equation make the function go to zero:

Y'=3xy-3x-12

Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12

F(-2,-1)=[6]-[-6]-12

F(-2,-1)=6+6-12

F(-2,-1)=12-12

F(-2,-1)=0

Solving for y

3xy-3x-12=0

y=4/x+x

Making y=0

$\frac{4}{x}+x=0$

$x^{2} =-4$

$x=-2$

So the values make the function go to zero