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3 years ago

X^2÷x-y+y^2÷y-x simplify

Mathematics

1 answer:

Alex17521 [72]3 years ago

6 0

The answer to this is 0

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In one year, profit fell from $1.73 billion to $1.18 billion. What was the percent decrease in profit?

Vlada [557]

Answer:

31.7919075 % decrease

Step-by-step explanation:

To find the percent decrease

Take the original amount and subtract the new amount

1.73 billion - 1.18 billion =.55 billion

Divide by the original amount

.55 billion / 1.73 billion

.317919075

Change to percent form

31.7919075 % decrease

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3 years ago

What is - 4/5 times -5/7

andreev551 [17]

What is - 4/5 times -5/7?
20/35 or in simplified form 4/7

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3 years ago

Read 2 more answers

Are y'all doing Usa test prep?

Oksana_A [137]

I don't think i am doing that.

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4 years ago

A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requi

Vika [28.1K]

Answer:

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 180, \pi = \frac{14}{180} = 0.0778$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 - 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.0387$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 + 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.1169$

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

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3 years ago

Lesson 20 5h grade homework

LUCKY_DIMON [66]

1igjgjyuhr55cysrhgu8rsyggshrborbgxm

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3 years ago