First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
9514 1404 393
Answer:
(-3, 9), (-1, 11), (0, 12), (4, 16), (6, 18)
Step-by-step explanation:
The function definition tells you that adding 12 to the x-value will give you the value of f(x).
-3 +12 = 9, for example
The (x, f(x)) values for the table are shown above.
Answer:
omg that question is impossible to answer
Answer:
0.500 hour
Step-by-step explanation:
Givens
<em><u>Distance</u></em>
- Total Distance on the highway = 3hr * 60 miles / hr = 180 miles
- Distance in the city = 20 miles
- Total Distance = 180 + 20 = 200 miles
<em><u>Time</u></em>
- Time on the highway = 3 hours
- Time in the city = x
Formula
d /t = r
Solution
- Average rate = 57.14
- Total Distance / Total Time = average rate
- 200 / (3 + x) = 57.14 Multiply both sides by 3 + x
- 200 = 57.14 * (3 + x) Remove the brackets
- 200 = 57.14*3 + 57.14x Multiply the factors on the right
- 200 = 171.42 + 57.14x Subtract 171.42 from both sides.
- 200 - 171.42 = 171.42 - 171.42 + 57.14x So the subtraction
- 28.58 = 57.14x Divide by 57.14
- 28.57/57.14 = x
- x = 0.500 hour Answer
I think the rate is decreasing from:
(-infinity, ln9/3)
