The square root of four is two. To find the square root of four you find out what number, when multiplied by itself will get four. In this case, 2×2=4.
Given:
In the given triangle the measure of two angles are 102 degree and 28 degrees and the sides of the triangle are a, 27 cm, c.
To find:
The value of a.
Solution:
Let the given triangle be ABC, such that,
Using angle sum property of triangles, we get
According to the Law of Sines:
Therefore, the value of a is about 44.06 cm.
Ф =5π/6
The reference angle is the smallest angle that the terminal side of the angle makes with the x-axis.
Given that here π/2 < Ф < π, the angle is in the second quadrant.
In the second quadrant the signs are:
sine positive
cosine negative
tangent negative.
Furthermore, the reference angle is π - Ф = π - 5π/6 = π/6.
Then,
sin Ф = sin π/6 = 1/2
cos Ф = - cos π/6 = -√(3) / 2
tan Ф = - tan π/6 = -√(3) /3
