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amid [387]
3 years ago
15

are given the sets A = (even numbers less than 10) and B = (multiples of 3 greater than 3) A:name the communities A and B B:desc

ribe the community A n B​
Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

A n B = {6}

Step-by-step explanation:

Given he sets A = (even numbers less than 10) and B = (multiples of 3 greater than 3)

A = {2, 4, 6, 8}

B = {3, 6, 9, 12, 15...}

A n B includes the numbers are are common to both sets i.e number that we can find in both A and B.

From the set given, we can see that the only number that exists in both set is 6, hence;

A n B = {6}

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The maximum weight that a rectangular beam can support varies jointly as its width and the square of its height and inversely as
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\bf \textit{now we also know that }~~ \begin{cases} w=\frac{1}{4}\\ h=\frac{1}{3}\\ L=12\\ W=30 \end{cases}\implies 30=\cfrac{~~k\frac{1}{4}\left( \frac{1}{3} \right)^2~~}{12} \\\\\\ 360=\cfrac{k}{36}\implies 12960=k~\hfill \boxed{W=\cfrac{12960wh^2}{L}}

\bf \textit{when } \begin{cases} w=\frac{1}{4}\\ h=\frac{1}{2}\\ L=12 \end{cases}\textit{ what is \underline{W}?}\qquad W=\cfrac{12960\left( \frac{1}{4} \right)\left(\frac{1}{2} \right)^2}{12} \\\\\\ W=1080\left( \cfrac{1}{4} \right)\left( \cfrac{1}{4} \right)\implies W=1080\cdot \cfrac{1}{16}\implies W=\cfrac{135}{2}\implies W=67\frac{1}{2}

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3 years ago
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I really hope this helped, if there’s anything just let me know! ☻
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3 years ago
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