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3^2 + 7 • 2
3^2 = 3 • 3 = 9
9 + 7 • 2
7 • 2 = 14
9 + 14 = 23
Answer: 23 ☑️
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Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have
When t = 0, A(0) = 0 (since the forest floor is initially clear)
So, D = R - A =
when t = 0(at initial time), the initial value of D =
Answer:
$5.625
Step-by-step explanation:
Cost per pound of beef = $1.25 per pound
Number of pounds purchased = 3.5 pounds
Amount given to cashier = $10.00
Amount of change to receive from cashier =?
Amount issued to cashier - total cost of beef
Total cost of beef = (number of pounds * cost per pound)
Total cost of beef = (3.5 * 1.25) = $4.375
$10 - $4.375 = $5.625
It decreased from week one to week two by -1.875, then it started to increase from 0.625 then to 1.5 by week 4