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Free_Kalibri [48]
3 years ago
10

Is 1 25 greater than 1.6

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0
No, on a number line, 1 would be the smallest, then 1.25 then 1.5 and then 1.6 and then 2.
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Can someone please help me with math.
Umnica [9.8K]

Answer:

9) C. 35 + 0.12x = 44.36

10) B

11) A. 32

Step-by-step explanation:

9)

44.36 is the TOTAL so the equations have to EQUAL it.

PER mile means it's a variable so it's 0.12x:

35 is a constant so there's no variable attached:

35 + 0.12x = 44.36

10)

B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.

11)

0.1x + 0.25(46 - x) = 6.70

0.1x + 11.5 - 0.25x = 6.7

-0.15x = 6.7 - 11.5

-0.15x = -4.8

x = 32

5 0
3 years ago
(5 - 3)⁴ - 2(7) + 8² = ?
Veseljchak [2.6K]

Answer:

66

Step-by-step explanation:

(5 - 3)⁴ - 2(7) + 8²

PEMDAS

Parentheses first

(2)⁴ - 2(7) + 8²

Exponents

16 - 2(7) + 64

Multiply and divide from left to right

16 -14 +64

Add and subtract from left to right

2+64

66

7 0
3 years ago
48 packages /second = packages /minute
Gekata [30.6K]

Answer:

2880 packages/min

Step-by-step explanation:

48 × 60 = 2880

8 0
2 years ago
Read 2 more answers
A potential energy function is given by U = A x3 + B x2 − C x + D . For positive parameters A, B, C, D this potential has two eq
Ivenika [448]

Answer:

7.8655

Step-by-step explanation:

Given the functionl

U=Ax^3+Bx^2-cx+D

Where,

A=1.45J/m^3\\B=2.85J/m^2\\c= 1.7J/m\\D=0.6J

We have, replacing,

U=1.45x^3+2.85x^2-1.7x+0.6

We need to derivate and verify for stable equilibrum that,

\frac{d^2 U}{dx^2}>0

Then,

U'(x) = 4.32x^2+5.7x-1.7

Roots in,

x_1=-1.57008\\x_2=0.250636

We obtain U"(x), then we have

\frac{d^2U}{dx}=8.64x+5.7

For x=-1.57, U"(x)=-7.86549 Unestable

For x=0.250636 U"(x)=7.8655>0 Stable

7 0
3 years ago
A) Simplify<br> X-2<br> 7(x - 2)2
STatiana [176]

Answer:

7x^2 -28x +28

Step-by-step explanation:

7(x - 2)^2

7 ( x-2)(x-2)

Foil

7 ( x^2 -2x-2x+4)

Combine like terms

7( x^2 -4x+4)

Distribute

7x^2 -28x +28

6 0
3 years ago
Read 2 more answers
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