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UkoKoshka [18]
1 year ago
14

PLS HELP In circle A, secant EC and tangent BC intersect at point C. mЕВ = 171° and mBD 83°. What is mBCD?

Mathematics
1 answer:
liubo4ka [24]1 year ago
4 0

Answer:

∠ BCD = 44°

Step-by-step explanation:

the secant- tangent angle BCD is half the difference of the intercepted arcs, so

∠ BCD = \frac{1}{2} (EB - BD) = \frac{1}{2} (171 - 83)° = \frac{1}{2} × 88° = 44°

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