PLS HELP In circle A, secant EC and tangent BC intersect at point C. mЕВ = 171° and mBD 83°. What is mBCD?
1 answer:
Answer:
∠ BCD = 44°
Step-by-step explanation:
the secant- tangent angle BCD is half the difference of the intercepted arcs, so
∠ BCD =
(EB - BD) =
(171 - 83)° =
× 88° = 44°
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Step-by-step explanation:
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