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4 years ago

Which of the following is an irrational number A.3\14 B.3.8 C.√38 D.√64

1 answer:

6 0

It is
$\sqrt{38}$
because an irrational number cannot be written as a simple fraction ( because there is not a finite number of numbers when written as a decimal ).

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Please simplify this please it’s due really soon!

iren2701 [21]

Step-by-step explanation:

$\frac{ {13}^{6} \div {13}^{8} \times {13}^{ - 4} }{ {13}^{ - 2} }$

You need to remember the properties of exponents: multiplication adds the exponents, division subtracts the exponents.

If you multiply two powers with the same base, the result will be the base to the sum of the powers.

If you divide two powers with the same base, the result will be the base to the difference of the powers.

In your case you will this:

${13}^{6 - 8 + ( - 4) - ( - 2)}$

That is:

${13}^{ - 4}$

Or:

$\frac{1}{ {13}^{4} }$

7 0

4 years ago

interpret r(t) as the position of a moving object at time t. Find the curvature of the path and determine thetangential and norm

Igoryamba

Answer:

The curvature is $\kappa=1$

The tangential component of acceleration is $a_{\boldsymbol{T}}=0$

The normal component of acceleration is $a_{\boldsymbol{N}}=1 (2)^2=4$

Step-by-step explanation:

To find the curvature of the path we are going to use this formula:

$\kappa=\frac{||d\boldsymbol{T}/dt||}{ds/dt}$

where

$\boldsymbol{T}}$ is the unit tangent vector.

$\frac{ds}{dt}=|| \boldsymbol{r}'(t)}||$ is the speed of the object

We need to find $\boldsymbol{r}'(t)$ , we know that $\boldsymbol{r}(t)=cos \:2t \:\boldsymbol{i}+sin \:2t \:\boldsymbol{j}+ \:\boldsymbol{k}$ so

$\boldsymbol{r}'(t)=\frac{d}{dt}\left(cos\left(2t\right)\right)\:\boldsymbol{i}+\frac{d}{dt}\left(sin\left(2t\right)\right)\:\boldsymbol{j}+\frac{d}{dt}\left(1)\right\:\boldsymbol{k}\\\boldsymbol{r}'(t)=-2\sin \left(2t\right)\boldsymbol{i}+2\cos \left(2t\right)\boldsymbol{j}$

Next , we find the magnitude of derivative of the position vector

$|| \boldsymbol{r}'(t)}||=\sqrt{(-2\sin \left(2t\right))^2+(2\cos \left(2t\right))^2} \\|| \boldsymbol{r}'(t)}||=\sqrt{2^2\sin ^2\left(2t\right)+2^2\cos ^2\left(2t\right)}\\|| \boldsymbol{r}'(t)}||=\sqrt{4\left(\sin ^2\left(2t\right)+\cos ^2\left(2t\right)\right)}\\|| \boldsymbol{r}'(t)}||=\sqrt{4}\sqrt{\sin ^2\left(2t\right)+\cos ^2\left(2t\right)}\\\\\mathrm{Use\:the\:following\:identity}:\quad \cos ^2\left(x\right)+\sin ^2\left(x\right)=1\\\\|| \boldsymbol{r}'(t)}||=2\sqrt{1}=2$

The unit tangent vector is defined by

$\boldsymbol{T}}=\frac{\boldsymbol{r}'(t)}{||\boldsymbol{r}'(t)||}$

$\boldsymbol{T}}=\frac{-2\sin \left(2t\right)\boldsymbol{i}+2\cos \left(2t\right)\boldsymbol{j}}{2} =\sin \left(2t\right)+\cos \left(2t\right)$

We need to find the derivative of unit tangent vector

$\boldsymbol{T}'=\frac{d}{dt}(\sin \left(2t\right)\boldsymbol{i}+\cos \left(2t\right)\boldsymbol{j}) \\\boldsymbol{T}'=-2\cdot(\sin \left(2t\right)\boldsymbol{i}+\cos \left(2t\right)\boldsymbol{j})$

And the magnitude of the derivative of unit tangent vector is

$||\boldsymbol{T}'||=2\sqrt{\cos ^2\left(x\right)+\sin ^2\left(x\right)} =2$

The curvature is

$\kappa=\frac{||d\boldsymbol{T}/dt||}{ds/dt}=\frac{2}{2} =1$

The tangential component of acceleration is given by the formula

$a_{\boldsymbol{T}}=\frac{d^2s}{dt^2}$

We know that $\frac{ds}{dt}=|| \boldsymbol{r}'(t)}||$ and $||\boldsymbol{r}'(t)}||=2$

$\frac{d}{dt}\left(2\right)\: = 0$ so

$a_{\boldsymbol{T}}=0$

The normal component of acceleration is given by the formula

$a_{\boldsymbol{N}}=\kappa (\frac{ds}{dt})^2$

We know that $\kappa=1$ and $\frac{ds}{dt}=2$ so

$a_{\boldsymbol{N}}=1 (2)^2=4$

3 0

3 years ago

There are 4,000 undergraduates registered at a certain college. Of them, 364 are taking one course, 496 are taking two courses,

kykrilka [37]

Answer:

X=1, P = 0.091

X=2, P = 0.124

X=3, P = 0.115

X=4, P = 0.378

X=5, P = 0.264

X=6, P = 0.028

Step-by-step explanation:

To calculate the probability distribution of X, first we have to define the sample space.

In this case X=1,2,3,4,5,6. This are the values that X can take.

The probability is calculated as equal to the relative frequency of each of the values.

For X=1, P = 364/4000 = 0.091

For X=2, P = 496/4000 = 0.124

For X=3, P = 460/4000 = 0.115

For X=4, P = 1512/4000 = 0.378

For X=5, P = 1056/4000 = 0.264

For X=6, P = 112/4000 = 0.028

4 0

3 years ago

5(20 + ) = 100 + 95 im tryna watch anime but i gotta do another test

ryzh [129]

I think it would be 195 or it might be 195 or it might be 195 or it might be 195

5 0

3 years ago

Read 2 more answers

How long will it take you to ski a distance of 36 miles at a speed of 3 miles per 30 minutes

vaieri [72.5K]

36 ÷ 3 = 12
12 x 30 = 360 (mins)

The answer is that it would take you 360 minutes to ski a distance of 36 miles.
or you could say: t would take you 6 hours to ski a distance of 36 miles.

7 0

4 years ago