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3 years ago

Which point is on the graph of f(x)=6^x?

Mathematics

2 answers:

VikaD [51]3 years ago

7 0

Answer:

The point (1 | 6) is on the graph. --> C

barxatty [35]3 years ago

5 0

Answer:

C ) $(1,6)$

Step-by-step explanation:

Since in a function, we can pick random value for x then plug it in the function. Let's pick and plug some values:

$f(x)=6^{x}\Rightarrow f(0)=(0,1)\Rightarrow f(1)=6^{1}\Rightarrow f(1)=6\Rightarrow (1,6)$

By the order, the first value is for x, and the second one y.

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Mx” is the slop of this equation

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Can someone help me out with some pesky math quiz :) I put a pic

Sindrei [870]

1. Simplifying ∛54 gives 3∛2

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3. The expression (2j4k)^4/5 can be written as $\sqrt[4]{32j^{20}k^{5} }^{5}$ making the first option the correct option

4. simplifying $\sqrt[4]{16x^{4} y^{12} }$ will result to 2x∛y

5. simplifying $\sqrt[5]{2940x^{13} y^{7} }$ will result to $14x^{6} y^{3} \sqrt{15xy}$ making the last option the correct option

<h3>How to simplify $\sqrt[5]{2940x^{13} y^{7} }$ </h3>

<u>given data</u>

$\sqrt[5]{2940x^{13} y^{7} }$

= ( 2940 * x^13 * y^7 )^1/5

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}$

multiplying the values inside the parenthesis by ^1/2

$= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15xy)^{1/2}$

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Read more on equations here: brainly.com/question/22688504

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1 year ago

A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?

alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is $\frac{1}{13}$ .

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is $4\times 51!$ .

The probability that the last card dealt is an ace is

$P=\frac{4\times 51!}{52!}$

$P=\frac{4\times 51!}{52\times 51!}$

$P=\frac{4}{52}$

$P=\frac{1}{13}$

Therefore, the probability that the last card dealt is an ace is $\frac{1}{13}$ .

4 0

3 years ago

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julia-pushkina [17]

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Step-by-step explanation:

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3 - 18i - 3i - 18

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Answer: -15 - 21i

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