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sergejj [24]
3 years ago
10

1. 10^7 = 10,000,000​

Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

True

Step-by-step explanation:

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If at the beginning of july Minh sweeps up 80 grams of sand each day how much will she have at the end of july
Annette [7]

Answer: 2,480 grams of sand

Step-by-step explanation:

There are 31 days in July.

Minh sweeps up 80 grams every day in July so at the end of July, Minh should have:

= Number of days * Sand per day

= 31 * 80

= 2,480 grams of sand

8 0
3 years ago
$350 in the ratio 4:3
kherson [118]

Answer:

$200 : $150

Step-by-step explanation:

Sum the parts of the ratio, 4 + 3 = 7 parts

Divide the total by 7 to find the value of one part of the ratio.

$350 ÷ 7 = $50 ← value of 1 part of the ratio

4 parts = 4 × $50 = $200

3 parts = 3 × $50 = $150

8 0
3 years ago
2/20 divided by 8/10
raketka [301]

Answer:

1/8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help in your answer!​
mart [117]

Answer:

Two different transformations happen. Rotation/Reflection and translation (I say rotation/reflection because they can both put the parabola where it is after being transformed)

(Rotation- 180 degrees)

(Reflection across its it's starting point)

Translation- pushed up 4 points from negative 4 to 0 on the y-axis

When you put the parent function into a graph it is positive so the u is opening upward and starts at -4. Both sides of the u go through the points (0,0)and (4,0).

But in the transformed function is negative so the u opens downward. The sides going through the points (0,-4) and (4,-4)

I hope this makes sense

4 0
3 years ago
A dressmaker needs to cut 12-inch pieces of ribbon from rolls of ribbon that are 6 feet in length. How many 12-inch pieces can t
Natasha2012 [34]

Answer:

he can cut 60 strips or ribbon

Step-by-step explanation:

The dressmaker has 720 inches of ribbon

from each roll of ribbon, he can make 6 12-inch pieces or ribbon

she has 10 rolls

so 6(strips per roll) x 10(amount of rolls) = 60 strips :)

8 0
3 years ago
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