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miss Akunina [59]
4 years ago
5

What is the correct solution set for the following graph?

Mathematics
1 answer:
Molodets [167]4 years ago
7 0

Answer:

The correct solution set is a point in Quadrant II.

Step-by-step explanation:

You can see that if you extend the lines, they will eventually intersect at only one point. The quadrants start with I in the upper right corner, go II in the upper left corner, III in the bottom left corner, and IV in the bottom right corner. You can see that they will eventually intersect in the upper left corner, Quadrant II.

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Help me! <br>This is Algebra problem
aleksklad [387]

Answer:

They paid 16 3/4% tax

Step-by-step explanation:

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B2m%20-%201%7D%20%20-%20%20%5Cfrac%7B1%7D%7Bm%20%2B%202%7D%20%20%3D%201%20%
Scilla [17]

Answer:

m = 1

Step-by-step explanation:

<u>2(m+2) - (2m-1)</u> = <u>5</u>

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3 0
3 years ago
Please gimme a hand I appreciate it in advance!!!
inessss [21]

Answer:

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Step-by-step explanation:

They are corresponding angles.

7 0
2 years ago
Read 2 more answers
SCALCET8 3.11.501.XP. Find the numerical value of each expression. (Round your answers to five decimal places.) (a) sinh(ln(4))
raketka [301]

sinh(ln(4)) = (exp(ln(4)) - exp(-ln(4)))/2 = (4 - 1/4)/2 = 15/8 = 1.875

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6 0
3 years ago
Select ALL that apply
Maurinko [17]
<span>m=250-25w
Therefore the next equation is false
The next equation is also false because the amount never goes over 250.
m+25w=250
Therefore the next equation is false
The equation is false because it is impossible for the numbers to equal 10</span>
8 0
4 years ago
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